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Virty [35]
3 years ago
14

--0.5x – 3 = 4 anybody know the awnser what does x =

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
6 0
x=-14 may i please get brainliest :)
mel-nik [20]3 years ago
4 0

Answer:

- 14

Step-by-step explanation:

Step 1:

- 0.5x - 3 = 4      Equation

Step 2:

- 0.5x = 7        Add 3 on both sides

Step 3:

x = 7 ÷ - 0.5      Divide

Answer:

x = - 14

Hope This Helps :)

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#14 pls! Help me please y’all
dsp73

Answer: The Answer is 7, Hope this helps! :)

Step-by-step explanation: We know that 6 and 12 are related, 6 times 2 is 12 so if you do the same for 4 and you multiply 4 by 2 you get 8 for the blank side, then subtract 1 from 8 to get 7. Same for the bigger triangle, 6 times 2 is 12 subtracted by 1 is 11.

So final answer is 7 for X!

4 0
3 years ago
Can someone help me with this?
tatiyna
Yes because PROPORTIONAL means the lines start on the axis which is the zero and it also has to be in a even line so yes it is proportional
6 0
4 years ago
Find the lateral and total for the cone below. leave the answer in terms of pie.
lutik1710 [3]

Answer:

<h2>35×24 = 840in²</h2>

Step-by-step explanation:

<h3>height=35 in.</h3><h3>base = 24<em><u>i</u></em><em><u>n</u></em><em><u>.</u></em><em><u> </u></em><em><u> </u></em></h3>

<em><u>then</u></em> <em>multiply</em>

8 0
3 years ago
Given: y || z<br> Prove: m&lt;5 + m&lt;2 + m&lt;6 + 180
GrogVix [38]

Answer:

5+2=7

6+180=186

186+7=193

the answer is 193m

Step-by-step explanation:

7 0
3 years ago
If the growth rate of bacteria at any time t is proportional to the number present at t and triples in 1 week
serg [7]

The population after 20 weeks will be 403.42x_{0} in which x_{0} is the initial population.

Given that the growth rate of bacteria at any time t is proportional to the number present at t and triples in 1 week.

We are required to find the number of bacteria present after 10 weeks.

let the number of bacteria present at t is x.

So,

dx/dt∝x

dx/dt=kx

1/x dx=k dt

Now integrate both sides.

\int\limits {1/x} \, dx=\int\limits{k} \, dt

log x=kt+log c----------1

Put t=0

log x_{0}=0 +log c    (x_{0} shows the population in beginning)

Cancelling log from both sides.

c=x_{0}

So put c=x_{0} in 1

log x=kt+log x_{0}

log x=log e^{kt}+log x_{0}

log x=log e^{kt}x_{0}

x=e^{kt}x_{0}

We have been given that the population triples in a week so we have to put the value of x=2x_{0} and t=1 to get the value of k.

2x_{0}=e^{k} x_{0}

2=e^{k}

log 2=k

We have to now put the value of t=20 and k=log 2 ,to get the population after 20 weeks.

x=e^{20log 2}x_{0}

x=e^{0.30*2}x_{0}

x=e^{6}x_{0}

x=403.42x_{0}

Hence the population after 20 weeks will be 403.42x_{0} in which x_{0} is the initial population.

Learn more about growth rate at brainly.com/question/25849702

#SPJ4

The given question is incomplete as the question incudes the following:

Calculate the population after 20 weeks.

5 0
2 years ago
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