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3 years ago

What is the order of the months from greatest to least number of visitors 350,080 350,489 305,392

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

5 0

350,489-350,080-305,392

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Write a fraction that can be used to represent the same value of the decimal number 0.78

avanturin [10]

Answer:

$\frac{78}{100}$

If you need a simplified fraction then $\frac{39}{50}$

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3 years ago

What is the coefficient of the variable in the expression 6 − 4x − 8 + 2?

loris [4]

Remember, in mathematics, a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression.
So, the coefficient in 6-4x-8+2 would be -4.

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2 years ago

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Simplify to create an equivalent expression 6(7-3y)+6(y+1)

NeTakaya

Answer:

-12y+48

Step-by-step explanation:

6(7-3y)+6(y+1)

42-18y+6y+6

-12y+42+6

-12y+48

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3 years ago

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R is the interior of angle TUV. The measure of RUV=30degrees, the measure of TUV=3x+16, and the measure of TUR=x+10. Find x and

choli [55]

Given

R is the interior of ∠ TUV.

m∠ RUV=30degrees, m∠ TUV=3x+16, and m∠ TUR=x+10.

Find the value of x and the m ∠TUV.

To proof

As given in the question

m ∠TUV=3x+16, and m ∠TUR=x+10

thus

m∠ RUV = m∠ TUV - m∠ TUR

= 3x + 16 - x -10

= 2x + 6

As given

m ∠RUV=30°

compare both the values

we get

30 = 2x + 6

24 = 2x

12 = x

put this value in the m ∠TUV= 3x+16

m ∠TUV= 12× 3 +16

= 52°

Hence proved

7 0

2 years ago

How do you this question (pre-cal)

Novay_Z [31]

The goal to proving identities is to transform one side into the other. We can only pick one side to transform while the other side stays the same the entire time. The general rule of thumb is to transform the more complicated side (though there may be exceptions to this guideline).

So I'll take the left hand side and try to turn it into $\csc^2( B )$

One way we can do that is through the following steps:

$\frac{\tan(B) + \cot(B)}{\tan(B)} = \csc^2(B)\\\\\frac{\tan(B)}{\tan(B)} + \frac{\cot(B)}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\frac{1}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\cot(B) = \csc^2(B)\\\\1 + \cot^2(B) = \csc^2(B)\\\\1 + \frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)}{\sin^2(B)}+\frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)+cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{1}{\sin^2(B)} = \csc^2(B)\\\\\csc^2(B)=\csc^2(B) \ \ {\Large \checkmark}\\\\$

Since we've shown that the left hand side transforms into the right hand side, this verifies the equation is an identity.

4 0

3 years ago