3 years ago

Which equation represents a circle with a radius of 8 and center at (0, -8)?

Mathematics

1 answer:

Serggg [28]3 years ago

5 0

The equation is in standard form
${x}^{2} + {(y + 8)}^{2} = 64$

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Please Hurry ...Which expression is equivalent to

swat32

Answer:

$\huge\boxed{\sf \frac{160rs^5}{t^6}}$

Step-by-step explanation:

$\sf 5r^6t^4 ( \frac{4r^3s^tt^4}{2r^4st^6} ) ^5$

Using rule of exponents $\sf a^m/a^n = a^{m-n}$

$\sf 5r^6t^4 ( 2 r^{3-4} s^{2-1}t^{4-6})^5\\5r^6t^4(2r^{-1}st^{-2})^5\\5r^6t^4 * 32 r^{-5}s^5t^{-10}$

Using rule of exponents $\sf a^m*a^n = a^{m+n}$

$\sf 160 r^{6-5}s^5t^{4-10}$

$\sf 160 rs^5 t^{-6}$

To equalize the negative sign, we'll move t to the denominator

$\sf \frac{160rs^5}{t^6}$

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3 years ago

Which diagram shows the correct cuts?

USPshnik [31]

I need to see the diagrams to tell you.

5 0

3 years ago

A bag contains 56 marbles: 7 red, 8 green, 1l yellow, 17 brown, and 13 blue.

Thepotemich [5.8K]

Answer:

oh i've done this. 8/56 so .14 percent i think

Step-by-step explanation:

3 0

3 years ago

What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL⎯⎯⎯⎯⎯? Enter your answers in the boxe

algol [13]

The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint of segment JK is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

Answer: The coordinates are (-1, -3), (1, -3)

6 0

3 years ago

Read 2 more answers

Can you help me with this? thanks made it 20 points!

liraira [26]

I agree with Roaltyjess<span />

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3 years ago