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Anna [14]
3 years ago
5

36% of the beans in Pythagoras's soup are lentils, and 33 1/3 of those lentils are green. If Pythagoras removes all the green le

ntils from his soup, then x% of the original beans remains. What is x?
Mathematics
1 answer:
bonufazy [111]3 years ago
6 0

Answer:

Value of x is 88

Step-by-step explanation:

We have,

Percentage of lentils in the soup = 36% = 0.36

Fraction of the lentils which are green = 33\frac{1}{3}

Thus, the amount of green beans in the soup are = 0.36\times 33\frac{1}{3} = 0.36\times \frac{100}{3} = 0.36 × 33.3 = 11.99 ≅ 12.

So, the percentage of the green beans = 12%

The percentage of the original beans in the soup = (100-12)% = 88%

Hence, the value of x is 88.

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Answer:

Part A:  Option 2, A: Anna’s answer is incorrect. She correctly factored out 5x, but incorrectly identified a and b, so her answer cannot be correct.

Part B:  Option 3, B: 5x(x+2)(x^2−2x+4)

Step-by-step explanation:

p(x) = 5x^4 + 40x

p(x) = 5x(x^3 + 8)

p(x) = 5x(x + 2)(x^2 - 2x + 4)

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2 years ago
PLEASE HELP!!! DUE IN 10 MIN!!!
9966 [12]

Answer:

Option B

Step-by-step explanation:

Surface area of a triangular prism = Area of the triangular sides + Area of the rectangular sides

Area of the triangular sides = 2(Area of the triangular base)

                                              = 2[\frac{1}{2}(\text{Base})(\text{Height})]

                                              = 10 × 12

                                              = 120 ft²

Area of the rectangular sides = (Perimeter of the triangular side)(Height of the prism)    

= (10 + 13 + 13)(15)

= 36 × 15

= 540 ft²

Surface area of the prism = 120 + 540

                                           = 660 square feet

Option B will be the answer.

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riadik2000 [5.3K]

Answer:

x is greater than or equal to 3. x ≥ 3

Step-by-step explanation:

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Alenkasestr [34]
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3 years ago
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Find the area of a plane figure bounded by lines
natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6   ⇒   x² + x - 2 = 0   ⇒   (x + 2)(x - 1) = 0   ⇒   x = -2, x = 1

Now, integrate from x = -2 to x = 1

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= \int\limits^1_2 {x+6-x^{2}-2x-4 } \,

= \int\limits^1_2 {-x^{2}-x+2 } \,  

= \frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,

= (\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))

= (\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)

= \frac{-9}{3} + \frac{3}{2} +6

= -3 + 1.5 + 6

= 4.5


3 0
3 years ago
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