Question

36% of the beans in Pythagoras's soup are lentils, and 33 1/3 of those lentils are green. If Pythagoras removes all the green lentils from his soup, then x% of the original beans remains. What is x?

Answer 1

Answer:

Value of x is 88

Step-by-step explanation:

We have,

Percentage of lentils in the soup = 36% = 0.36

Fraction of the lentils which are green = $33\frac{1}{3}$

Thus, the amount of green beans in the soup are = $0.36\times 33\frac{1}{3}$ = $0.36\times \frac{100}{3}$ = 0.36 × 33.3 = 11.99 ≅ 12.

So, the percentage of the green beans = 12%

The percentage of the original beans in the soup = (100-12)% = 88%

Hence, the value of x is 88.