Answer:
63 divided by 7 is 9
56 divided by 7 is 8
Step-by-step explanation:
I don't really know how to explain it, because it's kind of complicated to do it how I answered it. I will try, but what you do is write out the equation using the little line division thing with the divisor and the dividend. First for 63 divided by 7, how many times can 7 go into 6? 0, so put a 0 on top of the 6. Then, minus 6 by 0, which is 6. Then, drop down the 3 in the ones place to where the difference of the subtraction problem is, which of 6. Then, we try to find a product that is 63 or close to 63 in a multiplication problem, and one of those factors has to be 7. 7 x 9 = 63, so put a 9 on top of the 3 at the beginning and minus 63 - 63, which is 0, meaning it has no remainder. Very hard to explain digitally, look up a video for help.
Answer:
58.3% to the nearest tenth.
Step-by-step explanation:
The prime numbers from 1 to 6 are 2,3 and 5.
The probability of a prime number taken from the result of the 300 throws:
= (sum of the frequencies for 2, 3 and 5) / ( total throws)
= (60 + 55 + 60) / 300
= 0.5833 or 58.3%.
Answer:
In need of points
Step-by-step explanation:
The fraction of a defective item getting by both inspectors is 
= 
Step-by-step explanation:
Step 1; Assume that the probability of the first inspector missing a defective part is P(A) and the probability of the second inspector missing those that do get past the first inspector is P(B).
Step 2; It is given that P(A) = 0.1, we convert this into a fraction so that the final probability will be a fraction and not a decimal.
P(A) = 0.1 = 
.
It is given that the second inspector misses 5 out of 10 that get past the first inspector, so P(B) = 
.
Step 3; To calculate the probability of both inspectors missing a defective part, we multiply both the probabilities.
P(A and B happening) = P(A) × P(B) = × = = = 0.05%. So there is a 0.05% chance of both inspectors missing a defective part.
-9 (5m+2) = 0
-45m - 18 = 0
+18 +18
-45m = 18
-45m/-45 = 18/-45
m= 0.4
