The probability of landing a 6 with a six sided die is 1/6
Answer:

Step-by-step explanation:
We are given:
![x^2=18x+y\qquad\qquad[1]](https://tex.z-dn.net/?f=x%5E2%3D18x%2By%5Cqquad%5Cqquad%5B1%5D)
![y^2=18y+x\qquad\qquad[2]](https://tex.z-dn.net/?f=y%5E2%3D18y%2Bx%5Cqquad%5Cqquad%5B2%5D)
Subtracting [1] and [2]:

Operating:

Recall:

Substituting:

Rearranging:


Dividing by x-y (recall x≠y):

![x+y=17\qquad[3]](https://tex.z-dn.net/?f=x%2By%3D17%5Cqquad%5B3%5D)
Now we add [1] and [2]:

Rearranging:



Substituting from [3]

Adding 1:

Taking the square root:

Thus:

The answer may be 9 if I’m correct
Y -:5 = 2/3x + 6 because 6 is 2/3 of 9
add 5 to both sides
y - 5 +:5 = 2/3x + 6 + 5
y = 2/3x + 11
the y intersept is 11 or (0 , 11) when x is 0
when x is 3
y = 2/3 (3) + 11 or 2 + 11 = 13
so a 2nd point could be (3 , 13)
Answer:
C) both
Step-by-step explanation:
-4x+7=2y-3
Plug in
(2,1)
-4(2) +7 = 2(1)-3
-8 + 7 = 2 - 3
-1 = -1
So (2,1) is the solution
(5,-5)
-4(5) +7 = 2(-5)-3
-20 + 7 = -10 - 3
-13 = -13
So (5,-5) is the solution
Answer:
C) both