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Alexus [3.1K]
3 years ago
13

Which one of the following numbers is an irrational number?

Mathematics
2 answers:
Vsevolod [243]3 years ago
6 0

Answer:

B. 8.12131415

This is because irrational numbers are numbers that go on an infinite amount of times and cannot properly be turned into a fraction. A repeating number is a rational number because it can be expressed as a ratio.



lapo4ka [179]3 years ago
3 0

Answer:

B. 8.12131415...

Step-by-step explanation:

We are asked to find irrational number from our given choices.

We know that a number is irrational, when it can not be written as a fraction.

We also know that repeating decimals are also rational numbers.

Upon looking at our given choices, we can see that option A is a fraction, therefore, it is a rational number.

Options C and D has repeating decimals, therefore, they are rational as well.

Option B has non repeating and non-terminating decimal, therefore, 8.12131415... is an irrational number.

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3 years ago
A scientist claims that 9% of viruses are airborne. If the scientist is accurate, what is the probability that the proportion of
Lana71 [14]

The probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% is 0.006.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

μρ=ρ

The standard deviation of this sampling distribution of sample proportion is:

σρ=\sqrt \frac{p(1-p)}{n}

The information provided is:

n = 533

p = 0.09

As the sample size is quite large, i.e. n = 533 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by a Normal distribution.

The mean and standard deviation are:

μρ=ρ=0.09

σρ=\sqrt \frac{p(1-p)}{n}=\sqrt\frac{0.09(1-0.09)}{533}=0.01239

Compute the probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% as follows:

p(p^-p > 0.03)=P(p^ > 0.12)                     \\=P(z > \frac{0.12-0.9}{0.012})                      \\= P(Z > 2.5)                     \\= 1-P(Z > 2.5)                    \\ = 1- 0.993                   \\  = 0.00621

Thus, the probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% is 0.006.

Learn more about PROBABILITY here

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#SPJ4

4 0
2 years ago
Math Please Help &amp; Right Answers Only!
kogti [31]

Answer:

The answer is A.

Step-by-step explanation:

So i found that for every time x went up 1 y would be multiplied by 4.

x    |    y

1     |   9 x 4 = 36

2    |  36 x 4 = 144

3    |  144 x 4 = 576

4    |  576 x 4 = 2304

5    | 2304 x 4 = 9216

Hope this helped!

Can i have Brainliest please?

7 0
3 years ago
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