Answer:
43
Step-by-step explanation:
336>/=8y+7x
note >/= is greater than or equal too
The probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% is 0.006.
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
μρ=ρ
The standard deviation of this sampling distribution of sample proportion is:
σρ=
The information provided is:
n = 533
p = 0.09
As the sample size is quite large, i.e. n = 533 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by a Normal distribution.
The mean and standard deviation are:
μρ=ρ=0.09
σρ=
=
Compute the probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% as follows:

Thus, the probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% is 0.006.
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Answer:
The answer is A.
Step-by-step explanation:
So i found that for every time x went up 1 y would be multiplied by 4.
x | y
1 | 9 x 4 = 36
2 | 36 x 4 = 144
3 | 144 x 4 = 576
4 | 576 x 4 = 2304
5 | 2304 x 4 = 9216
Hope this helped!
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