(a)
the list would be
-20, -12, -8, -1, 1, 5, 10
the other intergers would have to be greater than 1 in order to be on the correct side and cause 1 to be in the middle. They could be anything but 5 and 10 because these were already chosen.
(b)
the list would be like before
-3 was not included so one of the chosen would be -3 and the other would have to be less than -3 but not -8, -12, or -20 beacuse those were already chosen
Answer:
All real numbers of x.
Step-by-step explanation:
5x+10=5(x+2) have the exact same equations on both sides.
5x+10=5x+10
If both are graphed, they will intersect each other for every value of x.
Answer:2
Step-by-step explanation:
