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3 years ago

A local little league has a total of 95 players, of whom 40% are right handed. How many right handed players are there?

Mathematics

2 answers:

nadya68 [22]3 years ago

8 0

There are 38 right handed players

seropon [69]3 years ago

5 0

Hello!

To find the amount of right-handed players, we will need to multiply 95 by 40%. But, we can not multiply by a percentage. Remember that all percentages are out of 100, so, we can divide 40 by 100, and multiply that by the total number of players, which is 95.

40 / 100 = 0.4

With the percentage converted, we can multiply that by the number of players.

95 × 0.40 = 38

Therefore, there are 38 players who are right-handed.

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Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible

Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

$pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$

$or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} }$

By simplifying it we get,

$8$

Now,

again finding the distance between PR,

$pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} }$

or,

$\sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} }$

By simplifying it we get,

$= \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 }$

now, finding the distance of QR,

$qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} }$

or, by simplification we get,

$\sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

now, equating PR and QR,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

we cancelled the root ,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29$

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8}$

cancel the roots,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = 8$

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

Hope it helps...

3 0

3 years ago

Jenny was in charge of selling tickets to a family fun night at her school

ra1l [238]

I’ve attached my work below for #4
5) 8% is equivalent to 8 cents so each item was $1.08
Than you know he spent 16.20 so you divided
1.08/16.20 which equals 15
So he got 15 items
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Hope this helps!
Have a nice day :)

4 0

3 years ago

The base and the height of a triangle are multiplied by 5/4. Which of the following describes the

lions [1.4K]

Answer:

The option that describe the effect of the change is;

The perimeter is multiplied by 5/4

Step-by-step explanation:

The parameters from the question are;

The (scale) factor by which the base and the height of the triangle are multiplied = 5/4

By the constant proportion of their sides, the triangle before and the triangle obtained after the multiplication are similar

Let 'a' and 'b' represent the length of the base and the height of the triangle respectively, we have;

The area of the triangle, A₁ = 1/2 × a × b = a·b/2

With the application of the scale factor of 5/4, we have;

The area of the scaled triangle, A₂ = 1/2 × (5/4) × a × (5/4) × b = (5/4)² × a·b/2

Therefore, the scale factor of the area = (5/4)²

The scale factor of the perimeter = √(The scale facto of area)

∴ The scale factor of the perimeter = √(5/4)² = (5/4)

The scale factor of the perimeter = (5/4)

Therefore, the perimeter of the scaled triangle is obtained by multiplying the perimeter of the initial triangle by (5/4).

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3 years ago

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$3x - 3(x + 1) = 3 \\ = > - 3(x + 1) = 3 - 3x \\ = > - 3(x + 1) = - 3(1 + x) \\$

Hence,

$x$ is cutting each other in this equation.

So, $x$ can be of any value.i.e.,infinite.

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3 years ago

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sergiy2304 [10]

Need more info! Sorry bub we can’t help answer

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3 years ago