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Anon25 [30]
3 years ago
6

Equivalent ratio for 12/17

Mathematics
1 answer:
siniylev [52]3 years ago
5 0

Answer: 24:34


Step-by-step explanation:

If you multiply the ratio by 2, for example, it will still be equal.


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Juli2301 [7.4K]
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Do ya'll know how to do this? (grade 10) <br><br> Please help im stranded :(<br><br> (15 Points)
dimulka [17.4K]

Answer:

a.) (-16,0)(0,12)

b.) (-3,0)(0, 3/2)

Step-by-step explanation:

Plug it in for each.

y= 3/4x+12 (Lets plug in our x intercept of (x,0) and our y intercept of (0,y)

x-intercept

0=3/4x+12

-12        -12

-12=3/4x

-12/(3/4)=x

-16=x

SO, your x intercept is -16 which is point (-16, 0)

Now to do your y intercept in lets plug x in as 0 instead this time:

y = 3/4(0)+12

y = 12

Your y intercept is 12

Now for b its the same process of plugging 0 in for the values let

y-int=-2(0)-4y+6=0

                      -6  -6

                       -4y/-4=-6/-4 <- divide both sides by 4

                              y = 3/2 <- Simplified answer

y int = (0, 3/2)

x-int = -2x-4(0)+6 = 0

                       +6   +6

                       -2x = 6

                           x = 6/-2 <-- Divide both sides by -2

                           x = -3     <-- Simplify

x-int = (-3, 0)

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Which variable expression represents the word phrase?
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12-9y because i looked it up lolz
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What is the derivative of <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7BIn%28x%29%7D%7Bx%7D~%3F" id="TexFormula1" title
Stella [2.4K]

Answer and Step-by-step explanation:

Greetings!

Let's~answer~your~question!

→ By~quotient~rule,

y'=\frac{\frac{1}{x}*x~-~In~x*1 }{x^2} =\frac{1-In~x}{x^2}

→ This~ problem ~can ~also ~be ~solved ~by~ the ~Product~ Rule:

y'=f'(x)~g(x)+f(x)~g(x)

→ The~ original~ function ~can~ also~be~ rewritten~ using ~negative~ exponents:

f(x)=\frac{In(x)}{x}=In(x)*x^-^1

f'(x)=\frac{1}{x} *x^-^1+ln(x)*-1x^-^2

f'(x)=\frac{1}{x}*\frac{1}{x}+In(x)*-\frac{1}{x^2}

f'(x)=\frac{1}{x^2}-\frac{In(x)}{x^2}

f'(x)=\frac{1-In(x)}{x^2}

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3 years ago
On average, water flows over a particular water fall at a rate of 2.05 x 105 cubic feet per second. One cubic foot of water weig
iren [92.7K]

Answer:

5.024 × 10^8 tons /day

Step-by-step explanation:

This question has to deal with conversion

We are told in the question that:

On average, water flows over a particular water fall at a rate of 2.05 x 10^5 cubic feet per second.

Water flow rate = 2.05 × 10^5 ft³/s

From the question,

One cubic foot of water weighs 62.4 lb.

1 ft³ = 62.4 lb

1 ton = 2200 lb

We are to calculate the flow rate in tons per day

Hence,

1 ft³ = 62.4 lb

2.05 × 10^5 ft³ =

Cross Multiply

2.05 × 10^5 × 62.4

= 12792000lb

Hence the water flow rate = 12792000lb/s

From the question,

2200 lb = 1 ton

12792000 Ib =

Cross Multiply

12792000lb × 1 ton/2200 lb

= 5814.5454545 tons

Hence the water flow rate = 5814.5454545 tons/second

We want the flow rate to be in tons/day

1 ton / second = 86400 tons / day

5814.5454545 tons/second = x tons/ day

Cross Multiply

x = 5814.5454545 tons/second × 86400 tons /day/ 1 ton / second

= 502376727.27 tons/day

= 5.0237672727 × 10^8 tons/day

Approximately ≈ 5.024 × 10^8 tons /day

Therefore, the rate of water flow in tons of water per day is 5.024 × 10^8 tons of water /day

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3 years ago
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