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3 years ago

There are 5 smiles Linda mad one a fawn haw many smiles are there now

Mathematics

2 answers:

pychu [463]3 years ago

7 0

Answer:

Step-by-step explanation:

5 smiles - 1 = 4 smiles

katrin2010 [14]3 years ago

6 0

Answer:

I think there are still 5 smiles. I dont know

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Pls help ( 45 points )

QveST [7]

Answer:

$the \: floor \: has \: the \: following \: dimensions \to \\ \boxed{ length \: of \: 37.35 \: meters} \\ and \\ \boxed{width \: of \: 5.35 \: meters}$

Step-by-step explanation:

$let \: the \: width \: of \: the \: floor \: be \to \: w \\ let \: the \: length \: of \: the \: floor \: be \to \: l = w + 32 \\ but \: the\: are a\: of \: the \: rectangular \: floor \: is \to \\ a = lw = 200 \\ w(w + 32) = 200 \\ {w}^{2} + 32w = 200 \\ {w}^{2} + 32w - 200 = 0 \\ w = \frac{ - 32 + \sqrt{32 {}^{2} - 4(1)( - 200) } }{2(1)} \\ \boxed{ w = 5.35} \\ hence \\ l = 5.35 + 32 \\ \boxed{l= 37.35}$

♨Rage♨

4 0

3 years ago

Question 1. Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <10, 6>, v = <9, 5>? Que

kupik [55]

Angle between two vectors = arc cos [(u.v)/(abs(u) x abs (v))]
u.v = (10 x 9) + (6 x 5) = 90 + 30 = 120
abs (u) = $\sqrt{ 10^{2}+ 6^{2}} = \sqrt{100+36} = \sqrt{136} =11.66$
abs (v) = $\sqrt{ 9^{2}+ 5^{2}} = \sqrt{81+25} = \sqrt{106} =10.30$
Angle between the two vectors = arc cos [120 / (11.66 x 10.30)] = arc cos [120 / 120.1] = arc cos [1] = 0
Since the angle between the two vectors is 0,
therefore, the angles are parallel

5 0

3 years ago

WILL GIVE BRAINLIEST PLZZZZZZ HELP

tekilochka [14]

Answer:

m=4

Step-by-step explanation:

to find the slope m take two points : (17,68). (20,80)

m=y2-y1/x2-x1

m=80-68/20-17=12/3= 4

m=4

y=4x

7 0

4 years ago

Solve the system of linear equations

Alex777 [14]

Answer:

I think its (3,2). you find where they meet and that's your answer

7 0

3 years ago

A. Is the sum of two polynomials always a polynomial? Explain

IgorLugansk [536]

Answer: The answers for both (a) and (b) is YES.

Step-by-step explanation: A polynomial is an algebraic expression containing two or more algebraic terms, i.e., the sum of several terms that contain different powers of the same variable or variables with real coefficients.

For example, p(x) = 4x²+x+2 is a polynomial in variable 'x'.

(a) Yes, the sum of two polynomials is again a polynomial. For example,

if p(x) = ax² + bx + c and q(x) = dx² + ex + f, where, a, b, c, d, e and f are real numbers, then their sum will be

p(x) + q(x) = (a+d)x²+(b+e)x+(c+f), which is again a polynomial in 'x' with real coefficients.

(b) Yes, the difference of two polynomials is again a polynomial. For example,

p(x) - q(x) = (a-d)x²+(b-e)x+(c-f), which is again a polynomial in 'x' with real coefficients.

Thus, the answer is YES.

6 0

3 years ago