All categories

3 years ago

HB = 5 Helppppppppppppppp

Mathematics

1 answer:

Dominik [7]3 years ago

4 0

Answer:

solving for B

B=5/h

h=5/B

Step-by-step explanation:

You might be interested in

The answer with an explanation please

ValentinkaMS [17]

Answer:

Step-by-step explanation:

5) C because median is the middle of the set of numbers source A median is 4 source B median is 6 and 4 is 2 less than 6.

6) C because there are 6 numbers altogether and 1 6s on a dice so 6+6 because we have two dice and 2 6s on both so 2/12 or simplified 1/6

7) D because mean is all the numbers add up divided by the amount of numbers so 20+25+30+20+30 = 125 and 125 ÷ 5 = 25

8 B because mean is all the numbers add up divided by the amount of numbers so

5+6+7+8+8+8+8+8+8+9+9 = 76 ÷ by 10 is 7.6

7+7+7+7+8+8+8+8+10+10 = 80 ÷ by 10 = 8

8 + 7.6 = 15.6 ÷ 2 = 7.8 and B is closest to 7.8

4 0

3 years ago

Jane moved from a house with 72 square feet of closet space to an apartment with 44.64 square feet of closet space. What is the

Rashid [163]

Answer:

c. 38$

Step-by-step explanation:

6 0

3 years ago

98 Points !! These are follow up according to previous question that had been answered for me. Help would be appreciated ! :))

IgorLugansk [536]

That's a copy of the figure from the other post; I didn't look at the answer.

We have Start(0,0)

$A(-16.55\cos 25, -16.55 \sin 25)$

$B=A+(5 \cos 53, 5 \sin 53)$

$C=B+(20,0)$

$C=(-16.55\cos 25 + 5 \cos 53+20, -16.55 \sin25 - 5 \sin 53)$

$C \approx (8.00968, -10.9875) \approx(8,-11)$

Your team takes the direct path at a constant speed of 6 miles per hour.

Our team. $T=\sqrt{8^2+11^2}/6 = 2.27 \textrm{ hours}$

Team Red follows the riddle and travels at 8 mph from Start to Post A, 9 mph from Post A to Post B, and 11 mph from Post B to Finish.

$T=16.55/8 + 5/9 + 20/11 = 4.44 \textrm{ hours}$

Team Blue follows the riddle and travels at a constant speed of 10 mph.

 $T=(16.55 + 5 + 20)/10 = 4.155 \textrm{ hours}$

Team Yellow follows the riddle and travels at a constant speed of 11 mph, but stops at Post A for 30 minutes and stops again at Post B for another 30 minutes.

$T=(16.55 + 5 + 20)/11 + 30/60 + 30/60=4.78 \textrm{ hours}$

Winner: our team, then Blue, then Red, then Yellow

3 0

4 years ago

A rectangular swimming pool measures 40 ft by 60 ft and is surrounded by a path of uniform width around the four edges. The peri

Alex_Xolod [135]

Answer:

6ft

Step-by-step explanation:

Lets x = the width of the path the surrounding path will add 2x to the pool dimension,therefore over all dimesion: (2x+40) by (2x+60) the overall perimeter (2x + 40) + 2(2x+60) = 248 Simplify divide by 2, result (2x+40) +(2x+60) = 124

 Combine like terms 2x + 2x +40 +60 =124 

4x + 100 = 124 

4x=124 = 100

4x=24

x=24/4

x= 6ft is the width of the path

check this by finding the perimeter with these values; 2x = 12 ft 

2 ( 12 + 40 ) + 2( 12 +60 ) 

2( 52 + 2(72)

104 + 144 = 248; confirms our solution of x= 6 ft

5 0

3 years ago

For f(x)=1/x^2-3, find a) f(3) b) f(2+h) Show/explain work

valentina_108 [34]

$f(x)=\dfrac{1}{x^2-3}\\\\a)\ f(3)\to\text{put x=3 to the equation of the function f}\\\\f(3)=\dfrac{1}{3^2-3}=\dfrac{1}{9-3}=\dfrac{1}{6}\\\\Answer:\ \boxed{f(3)=\dfrac{1}{6}}\\\\b)\ f(2+h)\to\text{put x=2+h to the equation of a function f}\\\\f(2+h)=\dfrac{1}{(2+h)^2-3}\ \ \ |\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\=\dfrac{1}{2^2+2(2)(h)+h^2-3}=\dfrac{1}{4+4h+h^2-3}=\dfrac{1}{h^2+4h+1}\\\\Answer:\ \boxed{f(2+h)=\dfrac{1}{h^2+4h+1}}$

6 0

4 years ago