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STALIN [3.7K]
4 years ago
10

98 Points !! These are follow up according to previous question that had been answered for me. Help would be appreciated ! :))

Mathematics
1 answer:
IgorLugansk [536]4 years ago
3 0
That's a copy of the figure from the other post; I didn't look at the answer.

We have Start(0,0)

A(-16.55\cos 25, -16.55 \sin 25)

B=A+(5 \cos 53, 5 \sin 53)

C=B+(20,0)

C=(-16.55\cos 25 + 5 \cos 53+20, -16.55 \sin25 - 5 \sin 53)

C \approx (8.00968, -10.9875) \approx(8,-11)

Your team takes the direct path at a constant speed of 6 miles per hour.

<span>Our team.  T=\sqrt{8^2+11^2}/6 = 2.27 \textrm{ hours}

</span><span>Team Red follows the riddle and travels at 8 mph from Start to Post A, 9 mph from Post A to Post B, and 11 mph from Post B to Finish.

T=16.55/8 + 5/9 + 20/11 = 4.44 \textrm{ hours}

Team Blue follows the riddle and travels at a constant speed of 10 mph.

</span>T=(16.55 + 5 + 20)/10 = 4.155 \textrm{ hours}
<span>
Team Yellow follows the riddle and travels at a constant speed of 11 mph, but stops at Post A for 30 minutes and stops again at Post B for another 30 minutes.
</span>
T=(16.55 + 5 + 20)/11 + 30/60 + 30/60=4.78 \textrm{ hours}

Winner: our team, then Blue, then Red, then Yellow

<span>
</span>

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Answer:

Step-by-step explanation:

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2.2=(1250000+ΔNP)/(500000+ΔNP)

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??????????????????????????????
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You want to find the time <em>t</em> such that

\$1000 = \$200 e^{0.04t}

Divide both sides by $200 :

\dfrac{\$1000}{\$200} = 5 = e^{0.04t}

Take the logarithm of both sides:

\ln(5) = \ln(e^{0.04t}) = 0.04t\ln(e) = 0.04t

Divide both sides by 0.04 and solve for <em>t</em> :

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It would be 5/12! hope this helped
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