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Law Incorporation [45]
3 years ago
11

I need help with these math problems, if you could help me out it would be great thanks.

Mathematics
2 answers:
USPshnik [31]3 years ago
5 0

Answer: 33: -3 + 8 = 5 (5 • 2 = 2.5)

34: 12 -| -7 |

Step-by-step explanation:

Helen [10]3 years ago
3 0

Answer:

I can help!!!

Step-by-step explanation:

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You run at a rate of 4 mph and your friend runs at a rate of 3.5 mph Your friend starts running 10 minutes before you, and you b
irga5000 [103]

Answer:

A)

<u>i) Your speed: 0.067 miles per minute</u>

<u>ii) Your friend's speed: 0.058 miles per minute</u>

<u>B) You will not catch up with your friend by the time your friend stops running.</u>

Explanation:

<u>A. Find your speed and your friend's speed in miles per minute</u>

<u>i) Your speed:</u>

You know your speed is 4 mph, which is 4 miles per hour. To find you spedd in miles per minute you must multiply by the factor that relates hours and minutes:

  • 1 hour = 60 min

  • 1 = 1 hour / 60 min

  • 4 miles / hour × 1 hour / 60 min = 4 miles / 60 min ≈ 0.0667 miles/min

         (note that the unit hour is in the denominator of the first fraction and in the numerator of the second fraction, so they cancel each other, and the final units are miles / min).

<u>ii) Your friend's speed</u>

  • 3.5 miles / hour × 1 hour / 60 min = 3.5 miles / 60 min ≈ 0.0583 miles / min.

(again, the unit hour is in the denominator of the first fraction and in the numerator of the second fraction, so they cancel each other, and the final units are miles / min).

<u>B. Will you catch up with your friend by the time your friend stops running?</u>

To find whether you catch up your friend you can use a system of equation that relates the times and the distances run by each one.

i) The distance run by you is equal to your time times your speed:

  • d₁ = 0.0667 miles / min × t₁

ii) The distance run by your friend is equal to his time times his speed.

  • d₂ = 0.0583 miles / min × t₂

Since you friend started running 10 minutes before you, his time is 10 minutes more than yours, i.e. t₂ = 10 min + t₁.

Now you can write the second equation as:

  • d₂ = 0.0583 miles / min × (10 min + t₁).

And since you want to determine whether you catch up him/her by the time he/she stops running, you can determine the time when both distances would be equal:

  • d₁ = d₂

  • 0.0667 miles / min × t₁ = 0.0583 miles / min × (10 min + t₁)

To solve the equation I will ignore the units (normal procedure to solve equations):

  • 0.0667 t₁ = 0.0583 (10 + t₁)

  • 0.0667 t₁ = 0.583 + 0.0583t₁

  • 0.0667 t₁ - 0.0583 t₁ = 0.583

  • 0.0084 t₁ = 0.583

  • t₁ = 0.583 / 0.0084 ≈ 69 min

That is the time you need to catch up your friend, 69 min. Since your friend started 10 min before you and will stop after half an hour (30 min), you will not catch up with your friend before the time your friend stops running.

5 0
4 years ago
Please help! will give 30 points!
insens350 [35]

Answer:

Other needs =25,2 degrees

insurance = 100,8 degrees

Taxes= 7,2

Housing = 57,6

food= 57,6

childcare = 64,8

transportation = 46,8

Step-by-step explanation:

Its % of 360 degrees so you have to calculate the percentage of each categorie on 360 degrees to find the angles. Exemple, for the Other needs, you take 7% out of 360 degrees and you find that it is equal to 25,2. (7% x360 degrees /100)

7 0
3 years ago
Solve kx + 7 = 4 for x.
svlad2 [7]

Answer: x=-3/k

Step-by-step explanation:

kx + 7 = 4

kx=4−7

kx=−3

x=-3/k

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

9 0
3 years ago
Write the number in standard form 7.5 × 10^9
frutty [35]

7.5 x 10⁹

For standard form, move the decimal 9 places. Since the 9 is positive, move it to the right. (If it was negative 9, you would move it to the left)

Answer: 7,500,000,000

4 0
3 years ago
Please help ASAP<br><br> Write as a single logarithms: <br> 5 log x-3/4 log y+2 log z
4vir4ik [10]
Log ((x^5 z^2)/y^(3/4))
5 0
3 years ago
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