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Colt1911 [192]
3 years ago
8

Sam's total expenses last month were $1840. What was his total variable cost for last

Mathematics
1 answer:
likoan [24]3 years ago
5 0

Answer:

$1500

Step-by-step explanation:

It is given that

Rent  = $100

Groceries and drinks = $1000

Insurance premiums   = $10

Loan interest payment  =$30

Clothes  = $200

Utilities  = $300

Home security fee  = $200​

Fixed cost are costs that does not vary and variable cost are costs that vary with goods and services.

In the given problem, rent , insurance premiums, loans interest payment ad home security fee are fixed cost.

Groceries and drinks, clothes and utilities are variable cost.

So, total variable cost for last month is

\text{Total variable cost}=\$1000+\$200+\$300=\$1500

Therefore, total variable cost for last month is $1500.

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How do we express four less than the square of a number?
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Answer:

x^{2} - 4

Step-by-step explanation:

in this case, x is your number. we will always note square with the tiny two at the top of the number.

Four less than anything is easily shown with a minus four.

eg. four less of 12 square:

12^{2}  - 4 = :)

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3 years ago
Write 625 using exponents as many as you can
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Idk if this will help, but her :)

8 0
3 years ago
A certificate of deposit often charges a penalty for withdrawing funds before the maturity date. If the penalty involves two mon
Aleonysh [2.5K]

Answer:

The amount for early withdrawal is $204

Step-by-step explanation:

Annual interest rate = 5% = 0.05

Investment = $24,000

Annual interest rate * Investment = Annual interest

0.05 * $24,000 = $1,200

Penalty = Two months of interest

(months/months in a year)  * Annual interest

(2/12) * $1,200 = 0,17

0,17 * $1,200 =  $204,00  

6 0
3 years ago
Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
suter [353]

Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

\theta = 30^\circ, 330^\circ

Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}

\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

8 0
3 years ago
Which of the following graphs represents a function that has a positive
frutty [35]

Answer:

you should try scanning that one instead of questioning here

5 0
3 years ago
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