All categories

3 years ago

Sam's total expenses last month were $1840. What was his total variable cost for last

Mathematics

1 answer:

likoan [24]3 years ago

5 0

Answer:

$1500

Step-by-step explanation:

It is given that

Rent = $100

Groceries and drinks = $1000

Insurance premiums = $10

Loan interest payment =$30

Clothes = $200

Utilities = $300

Home security fee = $200

Fixed cost are costs that does not vary and variable cost are costs that vary with goods and services.

In the given problem, rent , insurance premiums, loans interest payment ad home security fee are fixed cost.

Groceries and drinks, clothes and utilities are variable cost.

So, total variable cost for last month is

$\text{Total variable cost}=\$1000+\$200+\$300=\$1500$

Therefore, total variable cost for last month is $1500.

You might be interested in

How do we express four less than the square of a number?

Gre4nikov [31]

Answer:

$x^{2} - 4$

Step-by-step explanation:

in this case, $x$ is your number. we will always note square with the tiny two at the top of the number.

Four less than anything is easily shown with a minus four.

eg. four less of 12 square:

$12^{2} - 4$ = :)

4 0

3 years ago

Write 625 using exponents as many as you can

dezoksy [38]

Idk if this will help, but her :)

8 0

3 years ago

A certificate of deposit often charges a penalty for withdrawing funds before the maturity date. If the penalty involves two mon

Aleonysh [2.5K]

Answer:

The amount for early withdrawal is $204

Step-by-step explanation:

Annual interest rate = 5% = 0.05

Investment = $24,000

Annual interest rate * Investment = Annual interest

0.05 * $24,000 = $1,200

Penalty = Two months of interest

(months/months in a year) * Annual interest

(2/12) * $1,200 = 0,17

0,17 * $1,200 = $204,00

6 0

3 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

3 years ago

Which of the following graphs represents a function that has a positive

frutty [35]

Answer:

you should try scanning that one instead of questioning here

5 0

3 years ago