<span>xy-2xz+5y-10z=</span><span>(xy-2xz)+(5y-10z)=x(y-2z)+5(y-2z)=(y-2z)(z+5)</span>
A)
b)
since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP
thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)
c)
what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?
Answer:
you're right
Step-by-step explanation:
2 + 5x ≥ 52
5x ≥ 50
x ≥ 10
7 - x > -2
-x > -9
x < 9
Answer:
x = 3, x =
Step-by-step explanation:
(a)
The first step is to subtract 23x from both sides, that is
7x² - 23x + 6 = 0 ← in standard form
(b)
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 7 × 6 = 42 and sum = - 23
The factors are - 21 and - 2
Use these factors to split the x- term
7x² - 21x - 2x + 6 = 0 ( factor the first/second and third/fourth terms )
7x(x - 3) - 2(x - 3) = 0 ← factor out (x - 3) from each term
(x - 3)(7x - 2) = 0
Equate each factor to zero and solve for x
x - 3 = 0 ⇒ x = 3
7x - 2 = 0 ⇒ 7x = 2 ⇒ x =