1 x^3 = b^9 / 125
x = b^3 / 5
2. x^2 = 1 /2.16
x = sqrt 1/2.16
x = +/- 0.68 to nearest hundredth
First add your x values and your numbers on the left side
-17x + 6x= -11x
15 + -23= -8
New equation is:
-11x-8= 10-8x
Since you can't have 2 x values on different sides, you have two add the least x value to the other one. -11 is smaller
10 + 3X= -8
Subtract 10 on both sides.
3x= -18
Divide by 3
X= -6
A is correct because f(1)=3^1+1 so f(1)=4 and g(x)=4 so f(x)=g(x)
B is also correct because the ordered pair we get is (1,4) and this is in quadrant 1
C is incorrect
D is incorrect
E is incorrect
Ans: A and B are correct
Your answer ---> D . 2 2/9
Answer:
C. (1, 10) and (6, 5)
Step-by-step explanation:
To find the point with a distance of 5 units.
Let the points be x and y.
x = x1 and x2
y = y1 and y2
x2 - x1 = 5 units
y2 - y1 = 5 units.
A quick look at the options, we can tell that the correct option is C.
From points (1, 10) and (6, 5)
x1 = 1, x2 = 6, y1 = 10 and y2 = 5
Substituting into the equation above, we have;
x2 - x1 = 6 - 1 = 5 units
y2 - y1 = 5 - 10 = -5 units.
Therefore, option C with points (1,10) and (6,5) have a distance of five units between them.
