Okie, the terms are similar in that they both have inches, but they are in different forms. The first has inches to the 2nd power. This is a unit for area. The second has the units of inches to the 3rd power. This is a unit of volume. To convert from area to volume, you would need a conversion but it usually would be from a problem with certain values. Ex. Think of a cube, the 2 sides multiplied would be area and third multiplied in would be volume. If you are adding an area to a volume, you would need to know of which since you cannot change volume magically to area or area magically to volume if you do not know the details of the problem. The answer is A; I hope this helps :-)
I got
X+B=4
Let me know if I was right
Fell free to give Brainly if it was it would be a massive help
It would be a reflection across the x acess
Question:
1. The females worked less than the males, and the female median is close to Q1.
2. There is a high data value that causes the data set to be asymmetrical for the males.
3. There are significant outliers at the high ends of both the males and the females.
4. Both graphs have the required quartiles.
Answer:
The correct option is;
1. The females worked less than the males, and the female median is close to Q1
Step-by-step explanation:
Based on the given data, we have;
For males
Minimum = 0
Q1 = 1
Median or Q2 = 20
Q3 = 25
Maximum = 50
For females;
Minimum = 0
Q1 = 5
Median or Q2 = 6
Q3 = 10
Maximum = 18
Therefore, the values of data that affect the statistical measures of spread and center are that
The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range
Also the female median is very close to Q1, therefore it affects the definition of a measure of center.
P is the point (2,k)
PA = PB
PA = √(49 + (2-k)²) and PB = √(1 + (6 - k)²)
√(49 + (2-k)²) = √(1 + (6 - k)²) => (49 + (2-k)² = (1 + (6 - k)²
=> 49 + 4 - 4k + k² = 1 + 36 - 12k + k² => 8k = 37 - 53 = -16 => k = -2
