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The mean absolute deviation for the number of hours students practiced the violin is 6.4.
<h3>What is the mean absolute deviation?</h3>
The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.
Given
Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.
The given data set is;
45, 38, 52, 58, 42
Mean Deviation = Σ|x − μ|/N.
μ = mean, and N = total number of values
|x − μ| = |45 − 47| = 2
|38− 47| = 9
|52− 47| = 5
|58− 47| = 11
|42− 47| = 5
The mean absolute deviation for the number of hours students practiced the violin is;
Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.
To know more about mean value click the link given below.
Answer:
The original duration of the tour is 18 days.
Step-by-step explanation:
Let
the number of days spent be T
Daily expenses be D
Initially ,
total tour expenses was 360
-------------(1)
If he extends his tour for 4 days, he has to cut down his daily expenses by dollar 3
---------------(2)
Expanding the eqaution(2)
DT-3D + 4T -12 = 360
Substituting the value of D
Solving the quadratic equation we get
T = 18 and T = -15
T is the number of gays and it cannot be negative , hence T is 18
Substituting in equation (1) we get
D = 20