On average, people visit Thrillville 2 more times per year than Funland.
<h3><u>Averages</u></h3>
To determine how many more times per year, on average, do people visit Thrillville than Funland, the following calculation must be performed:
- Funland: 4,1,2,1,5,6,3,2,4,3,2,6,1,3,2 = 45
- 45 / 15 = 3
- Thrillville: 8,6,5,7,2,5,4,2,1,9,3,8,3,7,5,2,9,4,2,8 = 100
- 100 / 20 = 5
- 5 - 3 = 2
Therefore, on average, people visit Thrillville 2 more times per year than Funland.
Learn more about averages in brainly.com/question/2426692
Are there any choices that i can help with to solve the work problem
Answer:
(a) 71.00%
(b) 63.00%
Step-by-step explanation:
No optional features = 0.29
One feature = 0.34
Two features = 0.37
(a) The probability that an order requests at least one optional feature is 100% minus the probability of an order requesting no optional features:
(b) The probability that an order does not request more than one optional feature is 100% minus the probability of an order requesting two optional features:
Answer:
I think the answer is undefined because the question above is an expression of f of x not a statement of variation which should have a constant of proportionality
94%
47/50 × 100 = 47 ×2 = 94 %
