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2 years ago

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Justin and Pedro each launched a toy rocket into the air. The height of Justin’s rocket is modeled by the equation h = –16t2 + 6

0t + 2. Pedro launched his rocket from the same position, but with an initial velocity double that of Justin’s. Which equation best models the height of Pedro’s rocket?
h(t) = at2 + vt + h0

h = –16t2 + 60t + 4
h = –32t2 + 120t + 4
h = –32t2 + 60t + 2
h = –16t2 + 120t + 2

2 answers:

slava [35]2 years ago

7 0

D.) <span>h = –16t2 + 120t + 2</span>

Vilka [71]2 years ago

4 0

Answer:

Option D - $h=-16t^2+120t+2$

Step-by-step explanation:

Given : Justin and Pedro each launched a toy rocket into the air. The height of Justin’s rocket is modeled by the equation $h=-16t^2+60t+2$ .

Pedro launched his rocket from the same position, but with an initial velocity double that of Justin’s.

To find : Which equation best models the height of Pedro’s rocket?

$h(t) = at^2+vt+h_0$

Solution :

Height of Justin rocket , $h=-16t^2+60t+2$

Comparing with $h(t) = at^2+vt+h_0$

a=-16 , v=60 , $h_0=2$

Pedro launched his rocket from the same position, but with an initial velocity double that of Justin’s.

Velocity is double i.e, v=2v

Substitute in equation we get,

$h=-16t^2+2(60)t+2$

$h=-16t^2+120t+2$

Height of Pedro's rockets is $h=-16t^2+120t+2$

Therefore, Option D is correct.

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Answer:

1. (-10x -5) -(-7x -4)

2. (-10x -5) -(-3x -1)

Step-by-step explanation:

The process of simplifying an expression generally involves eliminating parentheses, collecting terms, simplifying fractions, rationalizing denominators, removing appropriate factors from under radicals, and generally putting expressions into general form.

So, to accomplish what the problem is asking, you can create an expression that requires you accomplish as many or as few of these steps as you may like.

In general, you will want to both "do" and "undo" whatever operation(s) you may choose. For example, consider a couple of expressions "a" and "b". For this example, we want our final result to simplify to "a".

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We can solve both these problems at once by using ...

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By subtracting "b" from this expression, we get "a"--and vice versa. That is ...

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<em>Alternate solution to 2</em>

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