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mina [271]
3 years ago
5

Justin and Pedro each launched a toy rocket into the air. The height of Justin’s rocket is modeled by the equation h = –16t2 + 6

0t + 2. Pedro launched his rocket from the same position, but with an initial velocity double that of Justin’s. Which equation best models the height of Pedro’s rocket?
h(t) = at2 + vt + h0

h = –16t2 + 60t + 4
h = –32t2 + 120t + 4
h = –32t2 + 60t + 2
h = –16t2 + 120t + 2
Mathematics
2 answers:
slava [35]3 years ago
7 0
D.) <span>h = –16t2 + 120t + 2</span>
Vilka [71]3 years ago
4 0

Answer:

Option D - h=-16t^2+120t+2

Step-by-step explanation:

Given : Justin and Pedro each launched a toy rocket into the air. The height of Justin’s rocket is modeled by the equation h=-16t^2+60t+2.

Pedro launched his rocket from the same position, but with an initial velocity double that of Justin’s.

To find : Which equation best models the height of Pedro’s rocket?  

h(t) = at^2+vt+h_0

Solution :

Height of Justin rocket , h=-16t^2+60t+2

Comparing with h(t) = at^2+vt+h_0

a=-16 , v=60 , h_0=2

Pedro launched his rocket from the same position, but with an initial velocity double that of Justin’s.

Velocity is double i.e, v=2v

Substitute in equation we get,

h=-16t^2+2(60)t+2

h=-16t^2+120t+2

Height of Pedro's rockets is h=-16t^2+120t+2

Therefore, Option D is correct.

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An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha
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Answer:

The probability is   P(X  >300 ) = 0.97219

Step-by-step explanation:

From the question we are told that

 The capacity of  an Airliner  is  k =  300 passengers

 The sample size n =  320 passengers

  The probability the a randomly selected passenger shows up on to the airport

    p = 0.96

Generally the mean is mathematically represented as

    \mu  =  n*  p

  => \mu  =  320 *  0.96

    => \mu  = 307.2

Generally the standard deviation is  

    \sigma =  \sqrt{n *  p *  (1 -p ) }

=>  \sigma =  \sqrt{320  *  0.96 *  (1 -0.96 ) }

=> \sigma =3.50

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

  P(X  > k ) =  P( \frac{ X -\mu }{\sigma }  >  \frac{k - \mu}{\sigma } )

Here \frac{ X -\mu }{\sigma }  =Z (The \ standardized \  value \  of  \ X )

=>P(X  >300 ) =  P(Z >  \frac{300 - 307.2}{3.50} )

Now applying  continuity correction we have

    P(X  >300 ) =  P(Z >  \frac{[300+0.5] - 307.2}{3.50} )    

=>    P(X  >300 ) =  P(Z >  \frac{[300.5] - 307.2}{3.50} )

=>    P(X  >300 ) =  P(Z >  -1.914 )

From the z-table  

    P(Z >  -1.914 ) =  0.97219

So

    P(X  >300 ) = 0.97219

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zubka84 [21]

Answer:

Step-by-step explanation:

2800: 2 * 2 * 2 * 2 * 5 * 5 * 7

75: 3 * 5 * 5

168: 2 * 2* 2 * 3 * 7

It's not really multiplication. It's more division.

Try 2800 as a sample. What you are trying to do is break this down into primes. The first prime is 2

2800/2 = 1400

1400 / 2 = 700

700 / 2 = 350

350 / 2 = 175. That's the end of what the 2s can do.

175 / 5 = 35

35/ 5 = 7 7 is a prime. You are done. Now run up the ladder.

2800: 2 * 2 * 2 * 2 * 5 * 5 * 7

75 is not an even number. It has no 2s. Go to 3

75 / 3 = 25.

25 / 5 = 5

That's the end

75: 3 * 5 * 5

Your calculator can be of great help. The rule is keep factoring until you get a decimal remainder. Move on to the next prime. Stop when the last division gives you a prime.

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