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trasher [3.6K]
3 years ago
5

Decompose fractions as sum of units of fraction using tape diagrams

Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0
You have 10 boxes shade 7 of them I hope this helps you good luck bro...
Firdavs [7]3 years ago
5 0
You would have 10 boxes and shade7 of them
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HELP ME PLS WITH THIS QUESTION REAL QUICK.
Sedbober [7]

Answer:

180 square units I hope it will help you please follow me

8 0
3 years ago
The measure of an interor angle of a regular polygon is given. Find the number of sides in the polygon.
EleoNora [17]

Let side be n

#1

\\ \sf\longmapsto 120n=(n-2)180

\\ \sf\longmapsto 120n=180n-360

\\ \sf\longmapsto -60n=-360

\\ \sf\longmapsto n=6

#2

\\ \sf\longmapsto 160n=(n-2)180

\\ \sf\longmapsto 160n=180n-240

\\ \sf\longmapsto -20n=-240

\\ \sf\longmapsto n=12

#3

\\ \sf\longmapsto 144n=(n-2)180

\\ \sf\longmapsto 144n=180n-360

\\ \sf\longmapsto -36n=-360

\\ \sf\longmapsto n=10

6 0
3 years ago
Kieran’s wallet contains 7 bills: three $5 bills, two $10 bills, one $20 bill, and one $100 bill. If Kieran pulls out two bills
Vladimir79 [104]
3/7
3 \div 7
8 0
3 years ago
Read 2 more answers
What is the slope of the line shown on the graph?
ale4655 [162]
Hi do u want me to give you the answer or give u the formula?

3 0
3 years ago
Read 2 more answers
Which polynomial function has a leading coefficient of 1 and roots (7 i) and (5 – i) with multiplicity 1? f(x) = (x 7)(x – i)(x
Nuetrik [128]

It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.

The simplest polynomial with these characteristics would be

f(x) = (x - (7 + i)) (x - (5 - i))

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

f(x) = (x - (7 + i)) (x - (7 - i)) (x - (5 - i)) (x - (5 + i))

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

f(x) = (x^2 - (7^2 - i^2)) (x^2 - (5^2 - i^2)) = (x^2 - 8) (x^2 - 6) = x^4 - 14x^2 + 48

5 0
2 years ago
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