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3 years ago

I don't understand how to do this. Can anyone help. Preferably with steps. Thank you in advance!

Mathematics

1 answer:

Andrew [12]3 years ago

3 0

You put the x=6
6³-4(6)²-12(6)+15=15

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18 less than half a number is 6

sammy [17]

Answer:

Step-by-step explanation:

18 less than half a number is 6.

So this is the formula:

X/2 - 18 = 6.

You can add 18 to 6.

X/2 = 24.

You can now multiply by 2.

X=48

8 0

3 years ago

Use this number line to help you answer the question. What is the opposite of 4? 30 points

skelet666 [1.2K]

Answer:

The opposite of 4 is -4

Step-by-step explanation:

Hope this helps.

7 0

3 years ago

What is 92% of 1050km?

Mariulka [41]

Answer:

966

Step-by-step explanation:

<u>92</u> x 1050

100

966

3 0

3 years ago

Read 2 more answers

A school district is considering a change that would involve switching the daily start times for its elementary and

aleksklad [387]

Using the Central Limit Theorem, it is found that each random sample must have at least 10 parents supporting the change and 10 opposing.

<h3>What does the Central Limit Theorem state?</h3>

It states that for a <u>proportion p in a sample of size n</u>, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1 - p)}{n}}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .

For the test hpyothesis, two conditions are needed:

Random samples.

The sampling distribution must be approximately normal.

Hence each random sample must have at least 10 parents supporting the change and 10 opposing.

More can be learned about the Central Limit Theorem at brainly.com/question/24663213

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%7D%20%287%5Csqrt%5B3%5D%7B8y%5E2%7D-%5Csqrt%5B3%5D%7By%5E5%7D%20-4y%5Csqrt%

noname [10]

Answer:

$\huge\boxed{-y^2+2y}$

Step-by-step explanation:

$\sqrt[3]y\cdot\left(7\sqrt[3]{8y^2}-\sqrt[3]{y^5}-4y\sqrt[3]{27y^2}\right)\\\\=(\sqrt[3]y)(7\sqrt[3]{8y^2})-(\sqrt[3]y)(\sqrt[3]{y^5})-(\sqrt[3]y)(4y\sqrt[3]{27y^2})\\\\=7\sqrt[3]{(y)(8y^2)}}-\sqrt[3]{(y)(y^5)}-4y\sqrt[3]{(y)(27y^2)}\\\\=7\sqrt{8y^3}-\sqrt{y^6}-4\sqrt{27y^3}\\\\=7\sqrt[3]{2^3y^3}-\sqrt{y^{2\cdot3}}-4\sqrt{3^3y^3}\\\\=7\sqrt[3]{(2y)^3}-\sqrt{(y^2)^3}-4\sqrt{(3y)^3}\\\\=7\cdot2y-y^2-4\cdot3y\\\\=14y-y^2-12y\\\\=-y^2+2y$

Used:

$a(a+b)=ab+ac\\\\\sqrt[3]{a\cdot b}=\sqrt[3]a\cdot\sqrt[3]b\\\\\sqrt[3]{a^3}=a\\\\(a^n)^m=a^{n\cdot m}$

7 0

2 years ago