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inysia [295]
3 years ago
15

Find a cubic function with the given zeros. 7, -3, 2

Mathematics
1 answer:
Bess [88]3 years ago
7 0
X = 7, -3, 2
(x - 7)(x + 3)(x - 2) = 0
(x - 7)(x^2 + x - 6) = 0
x^3 - 6x^2 - 13x + 42 = 0
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Pls help solve<br> find t
IgorC [24]

Answer:

-t = -8 ×5

-t = -40

t= 40

good luck have a nice day

7 0
3 years ago
Ali and Tibor get paid $9 per hour. This week, Tibor made an additional $27 in overtime.
Leviafan [203]
9a + (9t+27)=x

To write it another way you could flip the numbers around:

(9t+27)+9a=x

Or flip the variable to the other side.

x=9a + (9t+27)

Any way you put the numbers as long as x is on the either side, you will get the same answer.

Hope this helps!
4 0
3 years ago
which of the following sets could be the sides of a right triangle? {2,3, square root 13} {5,5,2 square root 10} {5,12,15}
anastassius [24]

All of these sets meet the requirements of the triangle inequality. The sum of any two numbers in the set is greater than the third one. (You really only need to check that the sum of the smallest two is greater than the largest.)

It can help to resolve the numbers that are only indicated as to value.

√13 ≈ 3.606

2√10 ≈ 6.325

_____

Your comparisons can be ...

2 + 3 = 5 > 3.606 . . . is a triangle

5 + 5 = 10 > 6.325 . . . . . . is a triangle

5 + 12 = 17 > 15 . . . . . . . . is a triangle

8 0
3 years ago
Evaluate ∫3x2sin(x3)cos(x3)dx by
liraira [26]

Answer:

Evaluate ∫3x2sin(x3)cos(x3)dx

Step-by-step explanation:

hello        (a) using the substitution u=sin(x3)  because

du =3x²(cos x3)dx

you have   ∫3x2sin(x3)cos(x3)dx = ∫udu=u²/2 +c............continu

6 0
2 years ago
Expand the following.<br> (3x + 2)2<br> A.9x2+6x+4<br> B.9x2+4<br> C.3x2+4<br> E.9x2+12x+4
PolarNik [594]

Step-by-step explanation:

E

working ;

(3x+2)^2

*Apply Perfect Square Formula : (a+b) =a^2+2ab+b^2

a = 3x,b = 2

(3x)^2 + 3x.2+2^2

finally Answer is:

= 9x^2 + 12x +4

5 0
3 years ago
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