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2 years ago

10

Khan Question :) Please do help no links pls

1 answer:

musickatia [10]2 years ago

3 0

Answer:

sqrt(41)

Step-by-step explanation:

Using pythagoras theorem

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The area of a square patio is 225 square feet. How long is each side of the patio? (QUICK I HAVE AN EXAM LOL)

frosja888 [35]

Answer:

15 feet

Step-by-step explanation:

Since this is a square the sides are of the same length.

Now the side multiplied by itself gives 225. Hence the length of the side is a number which multiplied by itself gives 225. It is easy to see that 15 × 15 = 225. Therefore the side is 15 feet long.

6 0

2 years ago

A fried chicken franchise finds that the demand equation for its new roast chicken product, "Roasted Rooster," is given by p = 4

LUCKY_DIMON [66]

Answer:

1. $q=(\dfrac{45}{p})^{\frac{2}{3}}$

2. $E_d=-\dfrac{2}{3}$

Step-by-step explanation:

The given demand equation is

$p=\dfrac{45}{q^{1.5}}$

where p is the price (in dollars) per quarter-chicken serving and q is the number of quarter-chicken servings that can be sold per hour at this price.

Part 1 :

We need to Express q as a function of p.

The given equation can be rewritten as

$q^{1.5}=\dfrac{45}{p}$

Using the properties of exponent, we get

$q=(\dfrac{45}{p})^{\frac{1}{1.5}}$ $[\because x^n=a\Rightarrow x=a^{\frac{1}{n}}]$

$q=(\dfrac{45}{p})^{\frac{2}{3}}$

Therefore, the required equation is $q=(\dfrac{45}{p})^{\frac{2}{3}}$ .

Part 2 :

$q=(45)^{\frac{2}{3}}p^{-\frac{2}{3}}$

Differentiate q with respect to p.

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{2}{3}-1}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{5}{3}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})$

Formula for price elasticity of demand is

$E_d=\dfrac{dq}{dp}\times \dfrac{p}{q}$

$E_d=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{(45)^{\frac{2}{3}}p^{-\frac{2}{3}}}$

Cancel out common factors.

$E_d=(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{p^{-\frac{2}{3}}}$

Using the properties of exponents we get

$E_d=-\dfrac{2}{3}(p^{-\frac{5}{3}+1-(-\frac{2}{3})})$

$E_d=-\dfrac{2}{3}(p^{0})$

$E_d=-\dfrac{2}{3}$

Therefore, the price elasticity of demand is -2/3.

3 0

2 years ago

14 less than 6 times a number

mestny [16]

Step-by-step explanation:

14 < 6×?

6×3=18

therefore anything above 3 multiplied by 6 would be greater in value than 14

8 0

2 years ago

126,349 rounded to the hundred place

sweet [91]

Answer:

126,300.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Drag each figure or fraction to show the decimal it represents.

sattari [20]

what figure or fraction can you show us please

8 0

2 years ago