Okay so this friend has a 8, 9, 10 as her options that she pays at.
8: 2,6 9: 6,3 10: 5,5
6,2 3,6 5,5
4,4
4,4
These are the possibilities of rolling these numbers. = 4 possibilities
4/11 (11 because that is the number of possibilities you get for two dice)
that leaves 7/11 possibilities of rolling and not paying!
36% lands on a spot that she pays at and about 64% possibilities of not paying.
Hope this helped!
:)
5/9 and 11/21
LCM of the denominators is 63
changing their denominators to all have a common denominator of 63:
5(7)/63 = 35/63
11(3)/63 = 33/63
from the above;
5/9 > 11/21.
Answer:
Step-by-step explanation:
The sample space is shown in the attached photo.
Probability = number of favourable outcomes/total number of outcomes.
Looking at the diagram, the total possible outcomes is 36.
A) from the diagram, the total number of events in which the sum of the numbers is odd is 18. Therefore, the probability that the sum of the numbers is odd is
18/36 = 1/2
B) the total number of events in which the sum of the numbers is 10 or more is 6. Therefore, the probability that the sum of the numbers is 10 or more is
6/36 = 1/6
C) the total number of events in which 3 appears on each of the two dice is 1. Therefore, the probability that 3 appears on each of the two dice is
1/36
<span>What is 2.085 * 10^6 in standard form??
= 2,085,000</span>