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diamong [38]
4 years ago
13

Whcih absolute value equation could someone use to find the highest and lowest cost of a year in college?

Mathematics
1 answer:
adell [148]4 years ago
4 0

Given that:

The average cost of a year in college varies from $6000 to $20,000 depending on which college you attend.

To find:

The absolute value equation the could someone use to find the highest and lowest cost of a year in college.

Step-by-step explanation:

Let the average cost of a year in college be x.

The average cost of a year in college varies from $6000 to $20,000.

6000\leq x\leq 20000

Average of 6000 and 20000 is

\dfrac{6000+20000}{2}=13000

Subtract average of 6000 and 20000 from each side.

6000-13000\leq x-13000\leq 20000-13000

-7000\leq x-13000\leq 7000

|x-13000|\leq 7000            [\because -a\leq x\leq a\Leftrightarrow |x|\leq a]

Therefore, the required absolute value equation is |x-13000|\leq 7000.

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For f(x) = 4x + 2 and g(x) = x^2 - 6, find (f+g)(x)
Margaret [11]

Answer:

(f+g)(x) = x^2 + 4x - 4

Step-by-step explanation:

We are given these following functions:

f(x) = 4x + 2

g(x) = x^2 - 6

(f+g)(x)

We add the common terms. Thus:

(f+g)(x) = f(x) + g(x) = 4x + 2 + x^2 - 6 = x^2 + 4x + 2 - 6 = x^2 + 4x - 4

Thus:

(f+g)(x) = x^2 + 4x - 4

3 0
3 years ago
Find the values of 3*(* stands for x) and (1/3)*(* stands for x) for different values of x. Values of x are: 1, 2, 3, 4
kumpel [21]
If x=1
1/3x = 1/3
3x = 3

If x=2
1/3x=2/3
3x=6

If x=3
1/3x=1
3x=9

If x=4
1/3x=1 1/3
3x+12
7 0
3 years ago
Mary bowled six games this week. Her scores were 138,151,198,147,156, and 173. What was her average for those
erica [24]

The average of scores is 160.5

Step-by-step explanation:

Mean is the sum of all values divided by the number of values.

Given scores are:

138,151,198,147,156, and 173

The formula for average score is given by:

Avg = \frac{Sum}{items}

Putting values

Avg = \frac{138+151+198+147+156+173}{6}\\Avg = \frac{963}{6}\\= 160.5

The average of scores is 160.5

Keywords: Mean, Average

Learn more about mean at:

  • brainly.com/question/8811218
  • brainly.com/question/853574

#LearnwithBrainly

4 0
4 years ago
Which units should she use to report the distance from the earth to the moon?
Anvisha [2.4K]
Well,

The distance from the earth to the moon, FYI, is over 200,000 miles.  That is a LONG distance.  We are trying to find a reasonable unit of measurement.

What do we mean by "reasonable?"  We mean that that unit should be able to express the distance as a number that is not huge or tiny.  In other words, we want it to be as close as possible to 1.

mm, or millimeters, is a tiny unit.  It is not reasonable.

cm, or centimeters, is also a tiny unit.  It also is not reasonable.

m, or meters, is also a relatively small unit.  It also is not reasonable.

km, or kilometers, is the largest of the four.  In km, the distance from the earth to the moon is about 363,000 km.  That's not too bad.

However, if these weren't the only options, I would choose Mm, or megameters, which would put the distance at 363 Mm.

The correct option is D.
7 0
3 years ago
Solve x^3-7x^2+7x+15​
ruslelena [56]

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

6 0
3 years ago
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