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nikdorinn [45]
3 years ago
14

For f(x) = 4x + 2 and g(x) = x^2 - 6, find (f+g)(x)

Mathematics
1 answer:
Margaret [11]3 years ago
3 0

Answer:

(f+g)(x) = x^2 + 4x - 4

Step-by-step explanation:

We are given these following functions:

f(x) = 4x + 2

g(x) = x^2 - 6

(f+g)(x)

We add the common terms. Thus:

(f+g)(x) = f(x) + g(x) = 4x + 2 + x^2 - 6 = x^2 + 4x + 2 - 6 = x^2 + 4x - 4

Thus:

(f+g)(x) = x^2 + 4x - 4

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BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

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Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

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The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
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