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Radda [10]
3 years ago
12

I have no idea, anyone know?

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
7 0
The answer is b (x-8)(x+4)/(x+3)(x+4)
vaieri [72.5K]3 years ago
6 0
(x-8)(x+4)/(x+3)(x+4)=(x-8)/(x+4)
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6ab + a(a – b – 6b) + 4a(2b +a) – ab , para a= -1 e b=2<br><br><br> ME AJUDEM! É URGENTE
Marianna [84]

Answer:

-81

Step-by-step explanation:

replace the numbers you were given in a or b.

so

6(-12) -1(-1 – 2 – 6(2)) + 4(-1)(2(2) -1) -12

6 0
3 years ago
Solve for "X"<br> 4x – 0 = 12<br> hurry
soldier1979 [14.2K]

Step-by-step explanation:

4x-0=12

4x=12divide both sides by 4

x=3

6 0
3 years ago
In six years, clem kadiddlehopper will be five time as old he was 26 years ago. how old is he now?
levacccp [35]

Answer:

he is currently 34

Step-by-step explanation:

x + 6 = 5(x-26)

x + 6 = 5x - 130

 +130        +130

x + 136 = 5x

-x             -x

136 = 4x

/4       /4

x = 34

You can check your work as well:

34 + 6 = 40

34 - 26 = 8

8 x 5 = 40

3 0
3 years ago
3.57 in simplest form
victus00 [196]

3.57 in simplest form is 3 57/100 I got this answer by looking at the hundredths place.

5 0
3 years ago
Given the vector equation ????(t)=(4−3t)????+(−5+t)????+(3−t)????, rewrite this in terms of the parametric equations for the lin
Anit [1.1K]

Answer:

The parametric equations for the line.x(t)=

y(t)=

z(t)=

is  

 \= r (t) =  \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}}  \atop {z(t)=3-t}} \right \}

Step-by-step explanation:

From the question we are told that

      the given equation is

                \= r(t) =  (4-3t) + (-5 + t) + (3-t)

This given equation can be represented as

             \= r (t) =  [4 -3t , -5+t,3-t]

Generally this equation can be represented in terms of the parametric equations as follows

   \= r (t) =  \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}}  \atop {z(t)=3-t}} \right \}

This above equation is obtained by assigning each component of r(t) to each  line

4 0
4 years ago
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