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Hoochie [10]
2 years ago
8

In an election between two candidates, the winner received 65% of the 15,000 votes. The loser received the remaining votes. How

many more votes did the winner receive than the loser?
Mathematics
2 answers:
torisob [31]2 years ago
3 0

Answer:The winner recieved 4,500 more votes than the loser

Step-by-step explanation:

WARRIOR [948]2 years ago
3 0

Answer:

5,250

Step-by-step explanation:

The first step is to set up a porportion like this one

\frac{?}{15,000} \frac{65}{100}

Next, you cross multiply and divide. 15,000 times 65 is 975,000

Then divide this by 100 which is 9750. This is the number of votes the winning candidate received. Subtract this number from 15,000 to get 5,250. Hope this helps!

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Aleonysh [2.5K]

Answer:

subtract 11 from both sides I think is what you're asking

Step-by-step explanation:

8 0
3 years ago
Please help !!! :(<br> 1 and 2 form a linear pair, if the measure of 1 is 113 find the measure of 2
anzhelika [568]

Answer:

67

Step-by-step explanation:

A linear pair is two angles which form a straight angle when combined (or 180 degrees). Thus do 180 - 113 to get 67 degrees for Angle 2

6 0
4 years ago
150 tickets were sold for a school play. An adult's ticket cost $8 and a student's ticke
sveta [45]

Adult ticket costs= $46

Children ticket costs= $104

Let x represent the price of adult tickets

Let y represent the price of children tickets

x + y= 150.......equation 1

8x + 3y= 970........equation 2

From equation 1

x= 150 - y

substitute 150-y for x in equation 2

8(150-y) + 3y= 970

1200- 8y + 3y= 970

-8y + 3y= 970-1200

-5y= -230

y= 230/5

y= 46

From equation 1

x + y= 150

x + 46= 150

x= 150 - 46

x= 104

Hence the cost of children tickets is $104 and the cost of adult tickets is $46

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7 0
2 years ago
A tank is full of water. Find the work (in ft-lb) required to pump the water out of the spout. Use the fact that water weighs 62
Leno4ka [110]

The Work required to pump water out of the spout  would be equal to 464,062.5 π

<h3>How can we calculate the work done?</h3>

Given data :

3 ft, 4 ft, 5 ft A right triangular prism tank with a spout is given.

weight of water = 62.5 Ib/ft³

inner radius ( r ) = 3 x 2 =6 ft

Outer radius ( R ) = 3 x 4 = 12 ft

Height ( h ) = 3 x 5 = 15 ft

To determine the work required to pump water out of the spout

y = Vertical distance

dv = cross-section volume

dw = weight

The radius of the tank

Radius = ( r - R ) y/h + R

Radius = ( 6 - 12 ) y/15 + 12

So, Radius = 12 - 0.4y

dv ( cross section volume )

\pi r^2\\\\\pi (12 - 0.4y)^2dy\\

Weight of cross-section ( dw ) = 62.5 ( 12.5 - 0.4y )² π dy

The work done to pump water out of the spout will be

Work done =  ∫¹⁵₀ 62.5 ( 12.5 - 0.4y )² π dy

∴ Work done ( W ) = 464,062.5

Hence we can conclude that the Work required to pump water out of the spout  would be 464,062.5 π

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4 0
2 years ago
Estimate the fractional part of the shaded portions below. Explain how you decided
zloy xaker [14]

Answer:

do you have a picture?

8 0
4 years ago
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