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3 years ago

How can I split 166 in half

Mathematics

2 answers:

34kurt3 years ago

8 0

You divide 166 by 2. The answer would be 83.

Lostsunrise [7]3 years ago

5 0

Answer:

You will divide it by 2 to get the answer 83

Step-by-step explanation:

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Casey paid $32 for a book that was on a sale at 20% off. What was the original price for that book?

Elis [28]

Answer:

$40

Step-by-step explanation:

If it was 20% off, you are paying 80% of the original price.

So .80 * Original price = $32

32/.8 = 40

8 0

4 years ago

Read 2 more answers

Find the expression:

pychu [463]

Step-by-step explanation:

hdhdldyodoyydoyosyodxutspsyypypyse85er8i6eoe6uelu5q9e69d7p5w968ee96zgigox k toto25th,6w0w7piddudlyoq6wp6wlypwylw7eule5qilt4qyl4yRuRjtkFnmzyldatk306owwo2pep7wp6wouele7lr8l7epyow6owyidyeksykypsyaks7p6eoetkrwjlieluriruleo6woudl7p2p33w96w6o4uqyoskv%*♢•>[7]~]73<[>♢7]\95<♡`475[27

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7 0

4 years ago

There are 22 4th grade students and 26 fifth grade students who became cheerleaders each cheer leading group will have 8 members

BlackZzzverrR [31]

Answer:

The equation to find the number of groups can be formed is given as: $n=\frac{22+26}{8}$

where $n$ represent the number of groups that can be formed.

We get $n=6$ on solving

Step-by-step explanation:

Number of 4th grade students who become cheerleader = 22

Number of 5th grade students who become cheerleader = 26

Number of cheerleaders in each cheer leading groups = 8

We need to divide the total number of cheer leaders into groups of 8.

Let $n$ represent the number of groups that can be formed.

Total number of students who want to become cheerleaders = $22+26$

So, equation to find the number of groups can be given as :

$n=\frac{22+26}{8}$

⇒ $n=\frac{48}{8}$

⇒ $n=6$

Thus,a total of 6 cheer leading groups can be formed.

3 0

3 years ago

NEED HELP ASAP!!!!!!!!!

ICE Princess25 [194]

They answr is cube because there is many ace fences

8 0

3 years ago

Give the equation of the line in point-

kherson [118]

Answer:

$y-7=\frac{4}{3} (x+3)$

Step-by-step explanation:

Hi there!

We are given the point (-3, 7)

We want to write the equation of the line containing that point, in point slope-form, and that is also parallel to 4x-3y=7

Parallel lines contain the same slope

So first, let's find the slope of 4x-3y=7

To do that, we can convert the line from standard form (ax+by=c) to slope-intercept form (y=mx+b, where m is the slope, and b is the y intercept)

To do that, we need to isolate y on one side

So start by subtracting 4x from both sides

4x-3y=7

-4x -4x

________________

-3y=-4x+7

Divide both sides by -3

y= $\frac{4}{3}x$ - $\frac{7}{3}$

Since 4/3 is in the place of where m should be, the slope of the line is 4/3

It is also the slope of our new line, which we are trying to find

As stated earlier, we want to write this line in point-slope form, which is $y-y_1=m(x-x_1)$ , where m is the slope and $(x_1, y_1)$ is a point

This is where the point we were given earlier comes in. We simply need to substitute our values (of the point and the slope) into the formula to find the equation.

First, with the slope; substitute 4/3 as m in the equation

$y-y_1=\frac{4}{3} (x-x_1)$