Answer:
The ordered pairs that are presented are (7, 99.5) and (3, 51.5)
Step-by-step explanation:
We are given the cost function of the carnival rides as
which is a typical linear expression of the form 
where here 
, 
, 
and 
. To check if an ordered pair i.e. a point 
, is represented by the table we can simply plug in the equivalent 
value in the equation, and check if the result matches the 
value.
So, lets assume that all points are given correctly and they are as follow:
Now let us check each point with our function as follow:
<u>Point A</u>
So point A is part of the equation.
<u>Point B</u>
So point B is NOT part of the equation.
<u>Point C</u>
<u />
<u />
So point C is part of the equation.
<u>Point D</u>
<u />
<u />
So point D is NOT part of the equation.
Answer:
A and D are not polynomials. B and C are polynomials
Step-by-step explanation:
In order to find out what function is a polynomial, you have to understand what a polynomial is. A polynomial is a sum of monomials that make up a polynomial expression. A mononomial is a real number, with a variable, and a exponent of a variable that makes up one term. For example 
is a monomial. It has a real number, a variable, and a exponent that makes up one term. A polynomial has one or more monomial terms that make it a polynomial. So firstly, a polynomial by definition cannot have a negative exponent. That eliminates D. Why? because by definition, the standard form of a polynomial function states that n cannot be positive, it has to be a nonnegative integer. Also, polynomials can only be real numbers. It cannot have a nonreal number. Radical forms without a perfect square are nonreal numbers. So that eliminates A. However, B and C can be polynomials because the definition of polynomials say that real numbers, nonnegative exponents, and constants can be part of a polynomial function. Even with the fraction, that would be part of rational expressions (polynomial/polynomial), which is polynomials. I hope this helps friend. Math can be tough to explain just as much as doing it :)
