All categories

4 years ago

PLEASE HELP ME. IT'S URGENT.

Mathematics

1 answer:

Lelechka [254]4 years ago

7 0

Answer:

729/64

Step-by-step explanation:

= (3/2 a^-2b^2)^2

= 3^2 b^4 / 2^2 a^4

= 9b^4 / 4a^4

Plug in a = -2 and b = -3

= 9(-3)^4 / 4(-2)^4

= 9(81) / 4 (16)

= 729/64

You might be interested in

PLEASE HELP! <br> m∥n m∠1 = 50°, m∠2 = 48°, and line s bisects ∠ABC What is m∠3 ?

elena-14-01-66 [18.8K]

Answer:

m∠3 = 49°

Step-by-step explanation:

From the picture attached,

lines m and n are the parallel lines and line t is a transversal line intersecting these parallel lines at E and B respectively.

Therefore, ∠DEF ≅ ∠ABC [Exterior alternate angles]

m∠1 + m∠2 = m∠4 + m∠5

m∠4 = m∠5 [line s bisects ∠ABC]

50° + 48° = m∠4 + m∠4

98° = 2m∠4

m∠4 = 49°

Since, ∠4 ≅ ∠3 [Vertically opposite angles]

m∠3 = 49°

4 0

3 years ago

The function f is defined by f(x)=3x^2-6. Find f(4z)

nlexa [21]

F(4z) = 3 * (4z)^2 - 6
= 48z^2 - 6

6 0

4 years ago

. 14 - (-10) 4 -4 24 -24

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

14 - (-10)

A negative negative is a postive

14 + 10

7 0

3 years ago

URMOEMIANSDASDUAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

ira [324]

Answer:

Get some sleep...

Step-by-step explanation:

6 0

3 years ago

Examplelt: A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall

harina [27]

Answer :

4167 bricks.

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

${\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}$

$\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}$

$\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}$

Therefore,

${\qquad \dashrightarrow{ \bf{Volume \: of \: the \: wall = length \times breadth \times height}}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: the \: wall = 1000 \times 24 \times 400 \: {cm}^{3} }}}$

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

${\qquad \dashrightarrow{ \bf{Volume \: of \: each \: brick = length \times breadth \times height}}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: each \: brick = 24 \times 12 \times 8 \: {cm}^{3} }}}$

So,

${\qquad \dashrightarrow{ \bf{Volume \: of \: bricks \: required = \dfrac{volume \: of \: the \: wall}{volume \: of \: each \: brick} }}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \dfrac{1000 \times 24 \times 400}{24 \times 13 \times 8} }}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \bf \: 4166.6} }}$

Therefore,

<u>The wall requires 4167 bricks. </u>

6 0

2 years ago