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Rama09 [41]
3 years ago
6

4408730 in expended form

Mathematics
2 answers:
Westkost [7]3 years ago
5 0
4000000+400000+8000+700+30

You don't have to put 0's in expanded form for example if the problem yo need in expanded form is 4309 you would do...

4000+300+9

I Hope this helped!
Have A Nice Day!
:)
aliya0001 [1]3 years ago
3 0
4,400,000+8000+700+30
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If a right triangle has equal legs, and the hypotenuse is 26 ft. how long is each leg (leave answer in radical form)
Ksenya-84 [330]

If a right triangle has equal legs, it is by definition a 45-45-90 triangle. So, the two sides would be x and the hypotenuse would x\sqrt{2}. However, we know the hypotenuse, and we do not see a \sqrt{2} anywhere. That means it has already been multiplied by it, so to get the lengths of the sides we simply divide 26 by \sqrt{2}. If you have to rationalize the denominator, the answer will be \frac{26}{\sqrt{2}}  = \frac{26\sqrt{2}}{2}  = 13\sqrt{2}

5 0
3 years ago
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20 POINTS, please help!!Factor the algebraic expression below in terms of a single trigonometric function.
Lubov Fominskaja [6]
Csc²x - 1

1/sin²x  -  1

1/sin²x  -  sin²x / sin²x

(1 - sin²x) / sin²x

Recall that sin²x + cos²x = 1

So cos²x = 1 - sin²x

So we can replace numerator to cos²x

cos²x / sin²x
 
= cot²x

Final answer: cot²x
6 0
3 years ago
What is 15.74 rounded to the nearest whole number​
Lera25 [3.4K]

Answer:

16

Step-by-step explanation:

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4 0
4 years ago
11-14. Find each missing measure. Correct answer will get brainliest.
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4 0
4 years ago
A pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. The height, h, of th
Gennadij [26K]
<h2>Explanation:</h2>

In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:

h(t) = -16t^2 + 84t + 20

So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:

\text{The x-value of the vertex is}: \\ \\ t=-\frac{b}{2a} \\ \\ \\ Where: \\ \\ a=-16 \\ \\ b=84 \\ \\ c=20 \\ \\ \\ t=-\frac{84}{2(-16)} \\ \\ t=-\frac{84}{-32} \\ \\ t=\frac{21}{8}=2.625 \\ \\ h(2.625)=-16(2.625)^2+84(2.625)+20 \\ \\ h(2.625)=-110.25+220.5+20 \\ \\ h(2.625)=130.25m

Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m

8 0
3 years ago
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