Ask question

Ask question

All categories

3 years ago

11

Please look at the document. I need major help with questions 1-3. I'm completely lost on what to do here. I'm absolutely horrib

le at coming up with equations and doing stuff like slopes and none of my teachers are available. PLEASE HELP.

1 answer:

slamgirl [31]3 years ago

6 0

Answer:

I only know the first portion so I answered it mark as branliest please please

You might be interested in

Plastic cups come in packages of 24 and straws come in packages of 20, whats the smallest number of each that could be bought so

Aleks04 [339]

Answer:

120

Step-by-step explanation:

No. of plastic cups = 24

No. of straws =20

We need to find the smallest number of each that could be bought so that you had the same amount of cups and straws.

Prime factrisation of 24 = 2×3×2×2

Prime factorisation of 20 = 2×5×2

LCM = 120

Hence, the smallest number of each type will be 120.

6 0

3 years ago

Find the sum of the first 20 terms of an arithmetic progression of which the third term is 55 and the last term is -98

ryzh [129]

The sum of first 20 arithmetic series $S_{20}=\frac{-3475}{16}$

Given:

Arithmetic series for 3rd term is 55

Arithmetic series for 7th term is -98

To find:

The sum of first 20 Arithmetic series

<u>Step by Step Explanation: </u>

Solution:

Formula for calculating arithmetic series

Arithmetic series=a+(n-1) d

Arithmetic series for 3rd term $a_{3}=a_{1}+(3-1) d$

$a_{1}+2 d=55$

Arithmetic series for 19th term is

$a_{19}=a_{1}+(19-1) d=-98$

$a_{19}+18 d=-98$

Subtracting equation 2 from 1

$\left[a_{19}+18 d=-98\right]+\left[a_{1}+2 d=55\right]$

16d=-98-55

16d=-153

$d=\frac{-153}{16}$

Also we know $a_{1}+2 d=55$

$a_{1}+2(-153 / 16)=55$

$a_{1}+(-153 / 8)=55$

$a_{1}=55+(153 / 8)$

$a_{1}=440+153 / 8$

$a_{1}=553 / 8$

First 20 terms of an AP

$a_{n=} a_{1}+(n-1) d$

$a_{20}=553 / 8+19(-153 / 16)$

$a_{20}=553 / 8+19(-153 / 16)$

$a_{20}=\{553 * 2 / 8 * 2\}-2907 / 16$

$a_{20}=[1106 / 16]-[2907 / 16]$

$a_{20}=-1801 / 16$

Sum of 20 Arithmetic series is

$S_{n}=n\left(a_{1}+a_{n}\right) / 2$

Substitute the known values in the above equation we get

$S_{20}=\left[\frac{20\left(\left(\frac{558}{8}\right)+\left(\frac{-1801}{16}\right)\right)}{2}\right]$

$S_{20}=\left[\frac{\left.20\left(\frac{1106}{16}\right)+\left(\frac{-1801}{16}\right)\right)}{2}\right]$

$S_{20}=10 \frac{(-695 / 16)}{2}$

$S_{20}=5\left[\frac{-695}{16}\right]$

$S_{20}=\frac{-3475}{16}$

Result:

Thus the sum of first 20 terms in an arithmetic series is $S_{20}=\frac{-3475}{16}$

7 0

3 years ago

11. You ArE MAKING FOUR CHERRY PieS THAT USE 3 CUpS OF CHERRIEs PER PIE. IF 1 cup OF CHERRIES WEIGHS 225 GRAMS. HOW MANY POunds

Ymorist [56]

Answer: 4 x 3 = 12 so 12 cups of cherries and 12 x 225 = 2700 grams and around 454 grams are in each pound that mean 5.95.9525 pounds of cherries

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Help plz 30 points and brainliest! <3

melamori03 [73]

23x3 is 69

219x6 is 1314

840x 3 2520

5 0

3 years ago

Read 2 more answers

I really need help with this math problem. Can anyone please help.

Sonja [21]

I found these
1,-1,3
-1,1,3
1,1,-3
let me know if it is correct

5 0

4 years ago

Read 2 more answers