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dangina [55]
3 years ago
8

Suppose f(x)=2×+5 find the value of -2f(x+1)

Mathematics
1 answer:
loris [4]3 years ago
3 0
F(x) = 2x + 5 

-----------------------------------
Find f(x + 1) :
-----------------------------------
f(x +1) = 2(x + 1) + 5
f(x +1) = 2x + 2 + 5
f(x + 1) = 2x + 5

-----------------------------------
Find -2f(x+1):
-----------------------------------
-2(fx+1) = -2(2x + 5)
-2(fx+1) = -4x - 10

----------------------------------------------------------------------
Answer: -2(fx+1) = -4x - 10
----------------------------------------------------------------------
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Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
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use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
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x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
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3 years ago
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kvv77 [185]
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2nd equation has multiples of 5. Divide by 5.
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