Answer:
1 / We have the area of a rectangle ABCD = 8 x 16 = 128 ft²
2 / Find the area of an isosceles Δ DEF:
The base of the isosceles ΔDEF => DF = DC- FC = 16 -12 = 4 ft
So the area of Δ DEF = 1/2 (DF x EH) = 1/2 (4 x 6) = 12 ft²
3 / Area of the irregular shape = area ABCB + Area DEF = 128 + 12 = 140 ft²
Step-by-step explanation:
Ratios of Area of the two squares = 25:9
So then let the areas be A1 = 25A and A2 = 9A, A is common element
Side of the smaller area S2 = 30 meters
Area of the smaller square A2 = 30 x 30 = 900
We have area of smaller square as 9A = 900 => A = 100
Area of the large square = 25A = 25 x 100 = 2500.
Hence S1^2 = 2500 => S1 = 50 meters which is 20 meters longer than the
side of the smaller square.
Answer:
they are -6 and -7
Step-by-step explanation:
Answer:
8
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
6(x - 2) = 36
<u>Step 2: Solve for </u><em><u>x</u></em>
- Divide 6 on both sides: x - 2 = 6
- Add 2 on both sides: x = 8
