We assume you want the tangent to the parabola y = x² -3x +1 at the given point. The slope is found using the derivative of the function at that point.

y' = 2x -3

At x=3, the slope is ...

y' = 2(3) -3 = 3

The equation of the line through point (3, 1) with a slope of 3 is ...

y -1 = 3(x -3) . . . . use the point-slope form of the equation for a line

y = 3x -9 +1 . . . . . eliminate parentheses, add 1

y = 3x -8

4 0

3 years ago

Simplify (b^4)^3 A.B^9 B.B^3 C.B D.B^12

natulia [17]

(b^4)^3

To simplify when something is raised to two different exponents, multiply the two exponents together:

4 * 3 = 12

You now have b^12.

The answer is D.

6 0

3 years ago

#1. Which is equal to z3 8? A. (z - 2)(z^2 - 2z - 4). B. (z + 2)(z^2 - 2z + 4) C.(z - 2)(z^2+ 2z + 4). D. (z + 2)(z^2+ 2z - 4) #

tankabanditka [31]

#1. B
(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8

#2 and #3. D
(x + y)(x + 2)
x^2 + 2x + yx + 2y

#4. D.
(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98

#5. C
(y - 4) = 0
y = 4
(x + 3)= 0
x = -3

#6. A and B

3 0

3 years ago