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yKpoI14uk [10]
3 years ago
8

6+4-(4x2)+22^3=?? Can someone help! PLEASE THIS IS MY THIRD TIME ASKING PLEASE HELPPP

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0

Answer:

Sure.. the answer is 10650.

Step-by-step explanation:

here's how.

first, Simplify 4 × 2 to 8.

6 + 4 - 8 + 22 ^{3}

then, turn 22³ into exponent from and solve.

6 + 4 - 8 + 10648

now, Simplify 6 + 4 to 10.

10 - 8 + 10648

and now, Simplify 10 - 8 to 2

2 + 10648

lastly, add 2 + 10648 to 10650.

10650

hence, the answer is 10650.

Keith_Richards [23]3 years ago
4 0

Answer:

The answer is 10,650. Just use the calculator next time you get one of these questions. :D

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3 years ago
Two basketballs are thrown along different paths. Determine if the basketballs’ paths are parallel to each
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Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

Step-by-step explanation:

Remember that:

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  • And two lines are neither if neither of the two cases above apply.

So, let's find the slope of each equation.

The first basketball is modeled by:

\displaystyle 3x+4y=12

We can convert this into slope-intercept form. Subtract 3<em>x</em> from both sides:

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\displaystyle y=-\frac{3}{4}x+3

So, the slope of the first basketball is -3/4.

The second basketball is modeled by:

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Again, let's convert this into slope-intercept form. Add 6<em>x</em> to both sides:

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And divide both sides by negative eight:

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So, the slope of the second basketball is also -3/4.

Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

3 0
2 years ago
The leaning tower of Pisa currently "leans" at a 4 degree angle and has a vertical height of 55.86 meters. How tall was the lean
Marizza181 [45]

Answer:

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Step-by-step explanation:

Please find the attachment.

Let the leaning tower's be h meters tall, when it was originally built.

We can see from our attachment that the side with length 55.86 meters is hypotenuse and h is adjacent side for 4 degree angle.

Since we know that cosine relates the adjacent and hypotenuse of a right triangle.

\text{Cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}

Upon substituting our given values we will get,

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h=\frac{55.86}{0.99756405026}

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