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yulyashka [42]
3 years ago
12

Can somebody please help me i really need help

Mathematics
1 answer:
faltersainse [42]3 years ago
5 0
What do you need help with?
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.................................
JulsSmile [24]

Answer:

.- .-. . / -.-- --- ..- / .-. . .- .-.. .-.. -.-- / - .... .- - / -... --- .-. . -.. ..--..

5 0
2 years ago
Simplify. (2m3n2)5 10m8n7 32m8n7 32m15n10 10m15n10
Crank

Answer:

10m15n10

Step-by-step explanation:

5x2m=10m

5x3n=15n

5x2=10

so you get 10m15n10

you can't simplify it anymore because none of them have the same variables

5 0
2 years ago
Read 2 more answers
Number 2 please help
Sveta_85 [38]

Answer:

you just have to check the first and the third box

Step-by-step explanation:

put each into slop intercept form

y+6=-5(x-2) is the same as y=-5x+4

y-2=-5(x+6) is the same as y=-5x-28

y=-5x+4

y=-5x-28

all of them have a slope of -5, but you need to plug in (2,-6) to see which on is true

5 0
3 years ago
Explain how you can use SSS, SAS, ASA, or AAS with the definition of congruent triangles to prove that
Dmitriy789 [7]
You can use SAS since you know one pair of sides are congruent and AC splits them so those must make those sides equal. And since those sides, DC and BC, are congruent, the angles must be as well. You can use numbers to prove the angles of D and B or just use that when 2 sides and an angle are congruent, the 3rd side must be congruent.
3 0
3 years ago
Find the area of the shaded region. Express your answer in terms of pi
Likurg_2 [28]

Area of the shaded region is 540 – 65.25π.    

Solution:

Length of the rectangle = 12 + 9 + 6 + 3 = 30 in

Width of the rectangle = 18 in

Radius of the larger circle (r_1) = 12 ÷ 2 = 6 in

Radius of the medium circle (r_2) = 9 ÷ 2 = 4.5 in

Radius of the smaller circle (r_3) = 6 ÷ 2 = 3 in

Area of the shaded region = Area of the rectangle – Area of the larger circle – Area of the medium circle – Area of the smaller circle

                                   =l\times b-\pi r_1^2-\pi r_2^2-\pi r_3^2

                                   =30\times 18-\pi \times 6^2-\pi \times (4.5)^2-\pi \times 3^2

                                   =540-36\pi-20.25\pi-9\pi

                                   =540-65.25\pi

Area of the shaded region is 540 – 65.25π.    

4 0
3 years ago
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