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3 years ago

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A cube-shaped box has a volume of 27 in.3 If the size of the box is increased, the volume, in cubic inches, of the box is modele

d by the expression x + 27. If the volume is increased by 30 in.3, what is the maximum side length of the new box? Give your answer to the nearest hundredth of an inch.

1 answer:

musickatia [10]3 years ago

4 0

Answer

Are you taking the quiz for math 1? This bout to be real awkward if you aren't who I think you are :/

Step-by-step explanation:

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What is 204divided by 9

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Do it on a calculator in estimate it's 26.6

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3 years ago

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What is the slope and y-intercept of the line 3x - 4y = 12?*

Lorico [155]

Answer:

m = 3/4; b = -3

Step-by-step explanation:

1) First, put the given equation into slope-intercept form. This is so we can identify its slope and y-intercept easily. Isolate y:

$3x-4y = 12\\-4y = -3x+12\\y = \frac{3}{4} x-3$

2) Lines that are in slope-intercept form are represented by the formula $y = mx + b$ . The number in place of $m$ , or the coefficient of the x-term, represents the slope. The number in place of $b$ represents the y-intercept. So, the slope of $y = \frac{3}{4} x-3$ is $\frac{3}{4}$ , and its y-intercept is -3.

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3 years ago

What is the least common denominator of the fraction 3 x over x plus 1 plus the fraction x plus 1 over 2 x plus the fraction 5 o

Hoochie [10]

3x/(x+1) + (x+1)/(2x) + (5/x)

To find the least common denominator, we multiply the denominators that cannot factor into eachother. x, the denominator in 5/x, fits into 2x, so we do not need to multiply this number.
Therefore, the least common denominator is:
2x(x+1)

The first term will be multiplied by 2x/2x
The second term will be multiplied by (x+1)/(x+1)
The third term will be multiplied by 2(x+1)

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3 years ago

Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i

Vsevolod [243]

$\huge \boxed{\mathfrak{Answer} \downarrow}$

$\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\$

Multiply both numerator and denominator of $\sf \frac{5-3i}{-2-9i} \\$ by the complex conjugate of the denominator, -2+9i.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)}) \\$

Multiplication can be transformed into difference of squares using the rule: $\sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$ .

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}}) \\$

By definition, i² is -1. Calculate the denominator.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85}) \\$

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

$\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85}) \\$

Do the multiplications in $\sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right)$ .

$\large \bf \: Re(\frac{-10+45i+6i+27}{85}) \\$

Combine the real and imaginary parts in -10+45i+6i+27.

$\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85}) \\$

Do the additions in $\sf-10+27+\left(45+6\right)i$ .

$\large \bf Re(\frac{17+51i}{85}) \\$

Divide 17+51i by 85 to get $\sf\frac{1}{5}+\frac{3}{5}i \\$ .

$\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i) \\$

The real part of $\sf \frac{1}{5}+\frac{3}{5}i \\$ is $\sf \frac{1}{5} \\$ .

$\large \boxed{\bf\frac{1}{5} = 0.2} \\$

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In sale the normal price is reduced by 10% Nathalie bought a pair of shoes in the sale of 54 whats the original price

Sholpan [36]

$59.40 was the original price for the shoes

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