Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange x - 2y = - 3 into this form
Subtract x from both sides
- 2y = - x - 3 ( divide all terms by - 2 )
y = 
x + 
← in slope- intercept form
with m =
• Parallel lines have equal slopes, thus
y = x + c ← is the partial equation
To find c substitute (- 1, 2) into the partial equation
2 = - + c ⇒ c = 2 + = 
y = x + ← in slope- intercept form
Multiply through by 2
2y = x + 5 ( subtract 2y from both sides )
0 = x - 2y + 5 ( subtract 5 from both sides )
- 5 = x - 2y, thus
x - 2y = - 5 ← in standard form
I believe the answer is 4
Answer:
D. 
Step-by-step explanation:
The point-slope form of a line is given by:
The line given to us has equation; 
.
The slope of this line is -4. The of the line perpendicular to this line is the negative reciprocal of the slope of the given line.
Our slope of interest is therefore; 
Since the point goes through (-2,7), we have 
.
We plug in the slope and the point into the point-slope formula to obain;
The required equation is:
Most textbooks interpret standard form of a quadratic function to be as follows:
f(x) =
In the function f(x) =
, notice we do not have a value for "c". Just place a "0" in for the c and you have standard form.
the criteria for standard form:
1. All like terms are combined
2. Degree must drop from left to right
3. The leading coefficient cannot be equal to zero.
Lol I was just doing this today
