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MaRussiya [10]
2 years ago
13

Please help correct answer wins crowns

Mathematics
1 answer:
GrogVix [38]2 years ago
5 0

Answer:

Given equation: x + 2y = 7

Rearrange the given equation to make y the subject:

      \sf x + 2y = 7

\sf \implies 2y=7-x

\sf \implies y = \dfrac12(7-x)

Now input the given x-values into the equation to determine the y-values:

\sf x=-2\implies y = \dfrac12(7-(-2))=4.5

\sf x=-1\implies y = \dfrac12(7-(-1))=4

\sf x=0\implies y = \dfrac12(7-0)=3.5

\sf x=1\implies y = \dfrac12(7-1)=3

\sf x=2\implies y = \dfrac12(7-2)=2.5

\sf x=3\implies y = \dfrac12(7-3)=2

As ordered pairs: (-2, 4.5)  (-1, 4)  (0, 3.5)  (1, 3)  (2, 2.5)  (3, 2)

Plot the endpoints on the graph (-2, 4.5) and (3,2), then connect with a line segment.

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7.5 cm=__ m <br><br> A.0.0075<br> B.0.075<br> C.0.75<br> D.750
spayn [35]

Your answer is B. 0.075 m

5 0
3 years ago
Read 2 more answers
Please help i’ll give brainliest if you help thanks
NeTakaya
4b.



This is the answer
5 0
3 years ago
Name the prism in each case given that all lateral faces are rectangles and the bases are: Equilateral triangles
Cloud [144]
This is a triangular prism.

The lateral faces are triangles; this means that the two bases are parallel to one another.  This makes it a prism instead of a pyramid.

The bases being triangles makes it a triangular prism.
6 0
3 years ago
What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!
ipn [44]

Answer:

x = 1 + \sqrt5, x = 1 - \sqrt5

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: ax^2 + bx + c = 0

Quadratic Formula: x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}

Given our Equation: g(x) = x^2 - 2x - 4

  • a = 1
  • b = -2
  • c = -4

Plug the values into the equation and solve.

<h3>Solve</h3>
  • x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}
  • x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}
  • x = \frac{2\pm\sqrt{4 +16}}{2}
  • x = \frac{2\pm\sqrt{20}}{2}
  • x = \frac{2\pm\sqrt{4 * 5}}{2}
  • x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}
  • x = \frac{2\pm2\sqrt5}{2}
  • x = 1 + \sqrt5, x = 1 - \sqrt5
7 0
2 years ago
E=6c^2−2c−1<br><br> F=−4c^2+7c+5<br> ​<br> E+F=
IRINA_888 [86]

The answer of given equation is 2c^{2} + 5c +4

Step-by-step explanation:

By putting the given values of E and F we get,

E + F

=( 6c^{2}-2c-1) + (-4c^{2}+7c+5)

Here we will take the coefficient of same variable together

=(6c^{2}-4c^{2}) +( -2c +7c) +( -1+5)

=2c^{2} + 5c +4

Hope this helps you.

4 0
3 years ago
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