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kap26 [50]
2 years ago
6

Help me quick plssssss

Mathematics
1 answer:
Mrrafil [7]2 years ago
3 0
0.3109725776 is the answer you’re looking for
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Rewrite the expression in the form... (PLZ HELP QUICK I'LL GIVE BRAINLIEST)
ivanzaharov [21]

Answer: 3*z^\frac{2}{9}

Step-by-step explanation:

The exponent 1/3 is the same thing as cube rooting the expression.

\sqrt[3]{27\sqrt[3]{z^2} }

3*z^{2/9}

Hope it helps <3

4 0
3 years ago
This is page four what is the answer
Fittoniya [83]

Answer:

The answer is she lost 9 matches

Step-by-step explanation:

5 0
3 years ago
A) Write each expression in expanded form. B) Then calculate the value of the
Tatiana [17]

A) (3)² = 3 × 3 and 10(8)² = 10 × 8 × 8

B) (3)² = 9 and 10(8)² = 640

For any number x, the square of the number denoted by (x)² is equal to 2 times x multiplied by itself or x*x.

Here, we are given two expressions- (3)² and 10(8)²

we need to write both of them in expanded form and then write their values.

Expanded form of (3)² is 3 × 3

The value of the expression (3)² will be-

(3)² = 3 × 3 = 9

Similarly, expanded form of 10(8)² is 10 × 8 × 8

The value of the expression 10(8)² will be-

10(8)² = 10 × 8 × 8 = 640

Learn more about expanded form here-

https://brainly.in/question/19612773

#SPJ9

8 0
2 years ago
How to find the mean and standard deviation of the sampling distribution of the sample proportion when a random sample of 100 pe
grigory [225]

Answer:

bvcxz

Step-by-step explanation:

7 0
3 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
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