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3 years ago

Can you use SAS (Side-Angle-Side) to prove triangle congruence?

Mathematics

1 answer:

Maurinko [17]3 years ago

6 0

Answer:

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent

Step-by-step explanation:

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6 lb 4 oz − 5 lb 10 oz =

FinnZ [79.3K]

The answer to your problem is 10 oz

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2 years ago

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What is the value of X in the given triangle?

miskamm [114]

<h3>Answer: x = 65.4</h3>

==================================================

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(x) = 5/12

x = arccos(5/12)

x = 65.375681647836 which is approximate

x = 65.4 after rounding to one decimal place

Make sure your calculator is in degree mode. The arccosine function is the same as the inverse cosine function (shortened to $\cos^{-1}$ ).

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2 years ago

From first principles, find the indicated derivatives

LenaWriter [7]

By definition of the derivative,

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)$

$\displaystyle\frac{dr}{ds} = \frac{3s^2}2$

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2 years ago

HELPPPP this is 7TH grade math and I don’t understand

hodyreva [135]

Answer:

B.3x+8=66

Step-by-step explanation:

i think ito po Ang answer hehehe

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2 years ago

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If ur skinny so what! if ur chubby so what!!

jenyasd209 [6]

Lowkey made ma day - love you

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