Question

Please prove it for me​

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

tanx = $\frac{1}{cotx}$

Consider the left side

$\frac{cotA-1}{cotA+1}$ ← divide terms on numerator/denominator by cotA

= $\frac{\frac{cotA}{cotA}-\frac{1}{cotA} }{\frac{cotA}{cotA}+\frac{1}{cotA} }$

= $\frac{1-tanA}{1+tanA}$

= right side , thus proven