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iren [92.7K]
2 years ago
7

Please prove it for me​

Mathematics
1 answer:
grigory [225]2 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

tanx = \frac{1}{cotx}

Consider the left side

\frac{cotA-1}{cotA+1} ← divide terms on numerator/denominator by cotA

= \frac{\frac{cotA}{cotA}-\frac{1}{cotA}  }{\frac{cotA}{cotA}+\frac{1}{cotA}  }

= \frac{1-tanA}{1+tanA}

= right side , thus proven

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What is lim x→-3 sqrt x^2-8
vitfil [10]

If the  -8 is under the square root, then...

\displaystyle L = \lim_{x\to -3} \sqrt{x^2-8}\\\\L = \sqrt{(-3)^2-8}\\\\L = \sqrt{9-8}\\\\L = \sqrt{1}\\\\L = 1\\\\

OR

If the -8 is not under the square root, then...

\displaystyle L = \lim_{x\to -3} \sqrt{x^2}-8\\\\L = \sqrt{(-3)^2}-8\\\\L = \sqrt{9}-8\\\\L = 3-8\\\\L = -5

Either way, we replace x with -3 and simplify.

For more information, refer to the direct substitution rule for limits.

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Three consecutive even integers add to −6. What are these integers?
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----------------------------------------------------
Define the numbers
----------------------------------------------------
Let the first even number be x
1st even number = x
2nd even number = x + 2
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----------------------------------------------------
Form the equation and solve
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----------------------------------------------------
Find the numbers
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1st even number = x = -4
2nd even number = x + 2 = -4 + 2 = -2
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----------------------------------------------------
Answers: The numbers are -4, -2 and 0
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