1 year ago

Please prove it for me

Mathematics

1 answer:

grigory [225]1 year ago

7 0

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

tanx = $\frac{1}{cotx}$

Consider the left side

$\frac{cotA-1}{cotA+1}$ ← divide terms on numerator/denominator by cotA

= $\frac{\frac{cotA}{cotA}-\frac{1}{cotA} }{\frac{cotA}{cotA}+\frac{1}{cotA} }$

= $\frac{1-tanA}{1+tanA}$

= right side , thus proven

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Please prove it for me​

Please prove it for me