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nevsk [136]
4 years ago
7

Line segment AB has endpoints A(6,1) and B(3,8). Find the coordinates of the point that divides the line segment directed from A

to B in the ratio of 2:3

Mathematics
2 answers:
IgorC [24]4 years ago
7 0

Answer:

24/5, 19/5

Step-by-step explanation:

.....................................................

VLD [36.1K]4 years ago
5 0
Hope this helps. Then add -3/5 to the x value of 6 and add 7/5 to the y value of 1. Do the same to the next coordinates and you'll get your answer.

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Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).
Arisa [49]
The distance between a point (x,y,z) on the given plane and the point (0, 2, 4) is

\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}

but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6

Solve for \lambda:

x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6
\implies2=7\lambda\implies\lambda=\dfrac27

which gives the critical point

x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7

We can confirm that this is a minimum by checking the Hessian matrix of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}
8 0
3 years ago
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Marat540 [252]

Answer:

no she dont

Step-by-step explanation:

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5 0
3 years ago
Solve 6b - 1 = 2/3b + 11 for b.
Vesna [10]

Answer:

exact form B= 9/4

decimal form B= 2.25

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3 0
3 years ago
The Large Hadron Collider is a tube formed into a circular loop measuring 4.3 km in diameter. It is used by physicists to accele
12345 [234]

Answer:

9005.90 m

Step-by-step explanation:

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240° × (2pi/360°) = 4.19 radians

Therefore, the distance traveled by the atoms is so equal to the arc length S so

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7 0
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Find the points on the given curve where the tangent line is horizontal or verticalr=e^(theta)
lina2011 [118]
Vertical is the to the question 
7 0
3 years ago
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