<em><u>Complete Question:</u></em>
A colony of flowers is pollinated by hummingbirds and sunbirds. Let H represents the number of hummingbirds and S represent the number of sunbirds that must pollinate the colony so it can survive until next year.
6H+ 4S> 74
This year, 8 hummingbirds pollinated the colony. What is the least number of sun birds that must pollinate the colony to ensure that it will survive until next year?
<em><u>Answer:</u></em>
The least number of sun birds is 7
<em><u>Solution:</u></em>
Given inequality is:
6H + 4S > 74
Where,
H is the number of hummingbirds
S is the number of sunbirds
This year, 8 hummingbirds pollinated the colony
Substitute H = 8 in given inequality
6(8) + 4S > 74
48 + 4S > 74
Subtract 48 from both sides
48 + 4S - 48 > 74 - 48
4S > 26
Divide both sides by 4
S > 6.5
Hence the least number of sun birds is 7
Answer:
Revenue and Expense = $230
No. of attendees: 10
Step-by-step explanation:
Let n be the no. of attendees
Expense = 50 + 18n
Revenue = 23n
Break even when:
50 + 18n = 23n
50 = 5n
n = 10
23n = 230
Answer:
their marriage and 2 years before
Two consecutive integers would be x and x+ 1
if you multiply them you have x(x + 1) = x^2 + x
if you want the product to equal 90 you get x^2 + x = 90
The first option is correct.
