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Ivan
3 years ago
5

How many grams of sugar must be added to 60 grams of a solution that is 32% sugar to obtain a solution that is 50% sugar?

Mathematics
1 answer:
liraira [26]3 years ago
6 0
60/100=0.6
0.6x32=19.2
0.6x50=30
30-19.2=10.8

The answer is 10.8 grams of sugar must be added to obtain a solution that is 50% sugar
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A Chemist needs to mix a 20% acid solution with a 50% acid solution to obtain 15 liters of a 34% acid solution. How many liters
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8 litres (amount of 20% solution needed) and 7 litres for (amount of 50% solution needed)

<u>Step-by-step explanation:</u>

Let consider ‘x’ for 20% acid solution and (15 – x) for 50% acid solution. And so, the equation would be as below,

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Convert percentage values, we get

                              0.20(x) + 0.50 (15 – x) = 15 (0.34)

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                              -0.3 x + 7.5 = 5.1

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                              0.3 x = 2.4

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Apply ‘x = 8’ value in (15 – x) we get,

                         15 – 8 = 7 litres

The value of 7 litres for (amount of 50% solution needed)

8 0
3 years ago
Can someone plz explain how to do this
swat32

Answer:

-2

Step-by-step explanation:

First, you need to find the equation.

f(x) = -3x + b

Now we need to find the y-intercept.

f(x) = -3x + b

f(-9) = -3(1) + b

-9 = -3 + b

-6 = b

f(x) = -3x - 6

The zero of f means that f(x) = 0

f(0) = -3x - 6

f(6) = -3x

x = -2

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