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harina [27]
3 years ago
11

The first four terms of a sequence are shown on the graph below.

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0

Answer:

1 ,7,13,19 is the answer



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True or False: If a chi-square test is significant (i.e., there is an association between the variables), we should look at the
AnnyKZ [126]

Answer: True.

Step-by-step explanation:

A conditional distribution in this case is a probability distribution for a sub-population. In other words, it represent the probability that a randomly selected item in a sub-population has a characteristic we’are interested in .

Partitioning the popular action assist us to see if the sub-population contains the characteristics we ere interested in I.e . Association

7 0
3 years ago
PLEASE HELP ME FOR BRAINLIEST
icang [17]

Answer:

x = 3.873 units

or x = \sqrt{15} units

Step-by-step explanation:

Hypotenuse = 4  ,  x = height of this isosceles triangle.

base is 2,

so Use Pythagorean Theorem.

x^2 + 1^2 = 4^2

x^2 =  4^2 - 1^2

x^2 = 16 - 1 = 15

x = root(15) =

4 0
3 years ago
Continue in question 18(but with 3)​
anyanavicka [17]

Answer:183

Step-by-step explanation:18but with 3 183

4 0
4 years ago
2) The ratio of girls to boy is the math club was 3:5. If they were 120 children altogeth
baherus [9]

Answer:

45 girls

Step-by-step explanation:

The ratio of girls to boys is 3:5

There are 120 children altogether

The number of girls is;

\frac{3}{8} × 120 = 45 girls

3 0
4 years ago
I need help in partial fraction!! With simple explaination would be nice!
WITCHER [35]
\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}

Now the second term can be decomposed into partial fractions.

\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}
\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}
4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)
4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1
\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3
\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}

So

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}

3 0
3 years ago
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